Parabolic Equations Using Vertex & Focus

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SUMMARY

The equation of the parabola with vertex at (2, 4) and focus at (2, 6) is derived using the formula (x-h)^2 = 4p(y-k). Substituting the vertex coordinates into the equation yields (x-2)^2 = 4(2)(y-4). The resulting equation simplifies to x^2 - 4x + 4 = 8y - 32. While isolating a variable is not strictly necessary, grouping constants and possibly dividing through by 8 can enhance clarity.

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Homework Statement



Write the equation of the parabola described.
Vertex: (2, 4) Focus: (2,6)

Homework Equations



(x-h)^2 = 4p(y-k)


The Attempt at a Solution



(x-2)^2 = 4(2)(y-4)
x^2-4x+4 = 8y -32

Do I need to isolate one of the variables, or can I leave the equation like this?
 
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I'd at least group your constants, to make it look nicer. After you've done that, you could divide through by 8, but it isn't strictly required (unless your teacher said so). Afterall, an equation for a circle is [tex]x^2 + y^2 = 1[/tex], and that doesn't have an 'isolated' variable.
 

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