Parallel Axis Theorem problem help

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Homework Help Overview

The discussion revolves around a conceptual question regarding the application of the parallel axis theorem in calculating the total area moment of inertia for a hollow region created by cutting a circle from a solid rectangle. The original poster presents a scenario involving a rectangle with a specified length and width, from which a circular area is removed.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore whether the negative area of the cut-out circle affects the moment of inertia calculation and question how this negative area interacts with the equations presented. There is also discussion about the centroid's position and its relevance to the problem.

Discussion Status

Some participants have provided insights into the relationship between the rectangle and the removed circle, suggesting that the centroid remains unchanged and that the parallel axis theorem may not be necessary in this specific case. However, there remains uncertainty regarding the treatment of negative areas in the moment of inertia equations.

Contextual Notes

The original poster expresses confusion about the implications of removing a shape and how it affects the calculations, particularly regarding the sign of the area and its contribution to the moment of inertia. There is an acknowledgment of the complexity introduced by different potential configurations of shapes.

LeFerret
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Homework Statement


This is moreof a conceptual question regarding the parallel axis theorem and area.
Lets say I have a solid rectangle with length L, and Width W.
I cut out a circle of radius R at the center.
When calculating the Total Area moment of inertia of the hollow region where the circle was cut out
is it Itotal=Irectangle-(Icentral-Ad2) or
Itotal=Irectangle-(Icentral+Ad2)
because I know the region cut out has a negative area, so I subtract that moment of inertia from the rectangle's moment of inertia, but I'm not sure if that negative carries over inside the parenthesis as well

Homework Equations


Iany=Icentral + Ad2

The Attempt at a Solution

 
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If you have a rectangle and then you remove a circular area from the center, the parallel axis theorem really doesn't come into play, because the centroid of the resulting figure hasn't changed from before the circular area was removed; i.e. I(net) = I(rectangle) - I(circle)
 
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I agree, but I wanted to explain what I was asking as simply as possible, the circle could be removed anywhere and it could be any series of shapes attached together. What I am confused on is if that negative area comes to play inside of the parenthesis or if it's |Ad^2|
 
LeFerret said:

Homework Statement


This is moreof a conceptual question regarding the parallel axis theorem and area.
Lets say I have a solid rectangle with length L, and Width W.
I cut out a circle of radius R at the center.
When calculating the Total Area moment of inertia of the hollow region where the circle was cut out
is it [STRIKE]Itotal=Irectangle-(Icentral-Ad2)[/STRIKE] or
Itotal=Irectangle-(Icentral+Ad2)
because I know the region cut out has a negative area,

You cut out a positive area, that makes a negative contribution to the total moment of inertia.


LeFerret said:
so I subtract that moment of inertia from the rectangle's moment of inertia, but I'm not sure if that negative carries over inside the parenthesis as well

Homework Equations


Iany=Icentral + Ad2

The Attempt at a Solution


The second equation is correct.

ehild
 
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thank you!
 
You are welcome:smile:

ehild
 

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