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Parallel Plates and Potential Difference

  1. Aug 22, 2010 #1
    Two parallel metal plates are separated by 1.5 cm and are maintained at a potential difference of 1200 V. A proton, initially at rest, is released from the poisitive plate. When it reaches the negative plate its speed is :

    So i know that potential energy is Vq.
    So i went 1200 V x 1.602 x 10-19, but I have no idea where to go from there.

    Thanks!
     
  2. jcsd
  3. Aug 22, 2010 #2
    Kinetic energy.
     
  4. Aug 22, 2010 #3
    Thanks a lot!
     
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