Parallel Plates and Potential Difference

Thread starter Dayna
Start date Aug 22, 2010
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Difference Parallel Parallel plates Plates Potential Potential difference

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Two parallel metal plates are separated by 1.5 cm and have a potential difference of 1200 V, creating an electric field that accelerates a proton released from the positive plate. The potential energy of the proton is calculated using the formula Vq, where V is the potential difference and q is the charge of the proton. After determining the potential energy, the discussion shifts to converting this energy into kinetic energy to find the speed of the proton when it reaches the negative plate. The relationship between potential energy and kinetic energy is crucial for solving the problem. Understanding these concepts is essential for calculating the proton's final speed accurately.

Aug 22, 2010

Dayna

Two parallel metal plates are separated by 1.5 cm and are maintained at a potential difference of 1200 V. A proton, initially at rest, is released from the poisitive plate. When it reaches the negative plate its speed is :

So i know that potential energy is Vq.
So i went 1200 V x 1.602 x 10-19, but I have no idea where to go from there.

Thanks!

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Aug 22, 2010

AJ Bentley

Kinetic energy.

Aug 22, 2010

Dayna

Thanks a lot!

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