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Parallel/series, calculate current drawn

  1. May 6, 2007 #1
    1. The problem statement, all variables and given/known data
    [​IMG]

    Find the current drawn.

    2. Relevant equations

    V=IR
    R1+R2+Rn
    1/ (1/R1)+(1/R2)+(1/R3)+(1/R4)

    3. The attempt at a solution

    R1=20,000ohms
    R2=70,000ohms
    R3=96,7000ohms
    R4=40,000ohms

    1/ (1/R1)+(1/R2)+(1/R3)+(1/R4) = 10037.44

    10=I(10037.44)
    I=.000996A

    Where did I go wrong?
     
  2. jcsd
  3. May 6, 2007 #2
    Think of the two 30Kohm resistors as being in parallel. Also, think of the 40 and 66.7 kohm resistors as being in parallel. Now, you have simplified that whole middle section into two resistors in series. you can go from here.
     
  4. May 6, 2007 #3
    Simple error, the 30K resistors are in parallel, as are the 40K and 66.7. These in turn are in series and that resultant in parallel with the other two branches.
     
  5. May 6, 2007 #4
    r1=20,000
    r2=15,000
    r3=25,004.7
    r4=40,000

    r2&r3 in parallel= 9,375.5

    20,000+9,375.7+40,000=69,375.5

    10=I(69,375.7)

    I=.000144A ??
     
  6. May 6, 2007 #5
    Almost R2 and R3 are in series.
     
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