Parallel/series, calculate current drawn

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Homework Help Overview

The problem involves calculating the current drawn in a circuit with multiple resistors arranged in both series and parallel configurations. The original poster provides specific resistor values and attempts to apply Ohm's law and formulas for series and parallel resistances.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the arrangement of resistors, suggesting that certain resistors should be considered in parallel or series to simplify the calculations. There are questions about the original poster's calculations and where errors may have occurred.

Discussion Status

The discussion is ongoing, with participants providing insights into the configuration of the resistors and suggesting corrections to the original poster's approach. There is no explicit consensus yet, as different interpretations of the circuit configuration are being explored.

Contextual Notes

Some participants note potential errors in the original poster's resistor values and calculations, indicating a need for clarification on the circuit setup. The original poster's values and the arrangement of resistors are under scrutiny.

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Homework Statement


http://img267.imageshack.us/img267/8159/untitled3ct1.gif

Find the current drawn.

Homework Equations



V=IR
R1+R2+Rn
1/ (1/R1)+(1/R2)+(1/R3)+(1/R4)

The Attempt at a Solution



R1=20,000ohms
R2=70,000ohms
R3=96,7000ohms
R4=40,000ohms

1/ (1/R1)+(1/R2)+(1/R3)+(1/R4) = 10037.44

10=I(10037.44)
I=.000996A

Where did I go wrong?
 
Last edited by a moderator:
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Think of the two 30Kohm resistors as being in parallel. Also, think of the 40 and 66.7 kohm resistors as being in parallel. Now, you have simplified that whole middle section into two resistors in series. you can go from here.
 
Simple error, the 30K resistors are in parallel, as are the 40K and 66.7. These in turn are in series and that resultant in parallel with the other two branches.
 
r1=20,000
r2=15,000
r3=25,004.7
r4=40,000

r2&r3 in parallel= 9,375.5

20,000+9,375.7+40,000=69,375.5

10=I(69,375.7)

I=.000144A ??
 
Almost R2 and R3 are in series.
 

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