Parametric Equation Homework: Show Constant of ##\frac{d^2y}{dx^2}/(dy/dx)^4##

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SUMMARY

The discussion focuses on demonstrating that the expression ##\frac{\frac{d^2y}{dx^2}}{\left(\frac{dy}{dx}\right)^4}## is a constant for the parametric equations ##x=t^3+1## and ##y=t^2+1##. The first derivative ##\frac{dy}{dx}## is calculated as ##\frac{2}{3t}##, and the second derivative ##\frac{d^2y}{dx^2}## is determined to be ##\frac{1}{3t}##. By substituting these derivatives into the given expression, the result confirms that the expression is indeed constant.

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Homework Statement


A curve is defined by the parametric equations ##x=t^3+1## and ##y=t^2+1##.
Show that ##\frac{\frac{d^2y}{dx^2}}{\left(\frac{dy}{dx}\right)^4}## is a constant.

Homework Equations

The Attempt at a Solution


So you differentiate both equations wrt ##t## then apply the chain rule to get ##\frac{2}{3t}##. Applying the chain rule after differenating twice to get ##\frac{d^2y}{dx^2}=\frac{1}{3t}##.
Substitute in both to get the result?
 
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squenshl said:

Homework Statement


A curve is defined by the parametric equations ##x=t^3+1## and ##y=t^2+1##.
Show that ##\frac{\frac{d^2y}{dx^2}}{\left(\frac{dy}{dx}\right)^4}## is a constant.

Homework Equations

The Attempt at a Solution


So you differentiate both equations wrt ##t## then apply the chain rule to get ##\frac{2}{3t}##. Applying the chain rule after differenating twice to get ##\frac{d^2y}{dx^2}=\frac{1}{3t}##.
Substitute in both to get the result?
Yes. Keep in mind that ##\frac{d^2 y}{dx^2} = \frac d {dx} \left(\frac {dy}{dx}\right) \cdot \frac {dt}{dx}##, using the chain rule.
 
Mark44 said:
Yes. Keep in mind that ##\frac{d^2 y}{dx^2} = \frac d {dx} \left(\frac {dy}{dx}\right) \cdot \frac {dt}{dx}##, using the chain rule.
Got it thanks a lot
 
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