Parametric Equations: Values of a, b & k for Circles A, B & C

  • Thread starter Thread starter ada0713
  • Start date Start date
  • Tags Tags
    Parametric
Click For Summary
SUMMARY

The discussion focuses on the parameterization of three circles A, B, and C using the equations x = a + k cos t and y = b + k sin t, where the values of a, b, and k are derived from their respective positions and radii. For Circle A, both a and b are 0 with a radius k of 5. Circle B has a center at (0, 5) with the same radius k of 5. Circle C is positioned at (10, -10) with a radius k of 2√10. The analysis confirms the correct parameterization based on the circles' geometric properties.

PREREQUISITES
  • Understanding of parametric equations
  • Knowledge of circle geometry
  • Familiarity with trigonometric functions
  • Ability to convert between parametric and Cartesian forms
NEXT STEPS
  • Study the derivation of parametric equations for different geometric shapes
  • Learn how to convert parametric equations to Cartesian form
  • Explore the properties of circles in coordinate geometry
  • Investigate the use of trigonometric functions in modeling circular motion
USEFUL FOR

Students studying geometry, mathematics educators, and anyone interested in understanding the application of parametric equations in describing circular shapes.

ada0713
Messages
44
Reaction score
0

Homework Statement



Each of the three circles A, B and C of the figure below can be parameterized by equations of the form
x = a + k cos t, y = b + k sin t, 0 ≤ t ≤ 2.
What can you say about the values of a, b and k for each of these circles?
(figure attached below)

The Attempt at a Solution


A: a and b are both zero because the circle is at the origin, k is 5 b/c the radius is 5
B: Since the circle moved up by 5, b is 5 and a is zero, k is agian 5 since the radius is 5
C: The circles's radius is 2[tex]\sqrt{10}[/tex] and it moved right and down by 10.
Thus, a is 10 and b is -10, and k is 2[tex]\sqrt{10}[/tex]

Above is how i came up with the answer but I'm not 100% sure.
Did I do it right, or is somthing wrong?
 

Attachments

Physics news on Phys.org
Well since the picture is pending approval, I would suggest to put the equation into Cartesian form and check the radius,centres and etc
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
Replies
12
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
2
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
8
Views
1K