Parametrizing a Portion of a Sphere Above z = √3 Using Cylindrical Coordinates

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Homework Help Overview

The discussion revolves around parametrizing a portion of a sphere defined by the equation x² + y² + z² = 7, specifically the part that lies above the plane z = √3, using cylindrical coordinates.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore various parametrization attempts using cylindrical coordinates, questioning the correctness of their approaches and notation. They discuss the relationship between x, y, and z in terms of r and θ, and the implications of the constraints imposed by the sphere and the plane.

Discussion Status

Several participants have provided different expressions for the parametrization and have raised questions about the notation and restrictions on r and θ. There is an ongoing exploration of how to correctly express the position vector and the necessary conditions for the parameters.

Contextual Notes

Participants note the importance of the constraints 0 < r < 2 and 0 < θ < 2π, derived from the conditions of the problem. There is also mention of potential confusion regarding the use of symbols and the need for clarity in notation.

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Homework Statement


Parametrize the portion of the sphere given by x2 + y2 + z2 = 7 that lies above z = √3. (use cylindrical coordinates)

Homework Equations


x2 + y2 = r2

The Attempt at a Solution


x = rcosθ
y = rsinθ
z = z
z = √3
x2 + y2 + (√3)2 = 7
x2 + y2 = 4
r2cos2θ + r2 sin2θ = 4
r2 (cos2 + sin2θ) = 4
r = 2
Is this the correct way of parametrization?
 
Last edited:
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Stan12 said:

Homework Statement


Parametrize the portion of the sphere given by x2 + y2 + z2 = 7 that lies above z = √3. (use cylindrical coordinates)

Homework Equations


x2 + y2 = r2

The Attempt at a Solution


x = rcosθ
y = rsinθ
z = z
z = √3
x2 + y2 + (√3)2 = 7
x2 + y2 = 4
r2cos2θ + r2 sin2θ = 4
r2 (cos2 + sin2θ) = 4
r = 2
Is this the correct way of parametrization?
Where is your parametrization ?

What's your final answer?
 
Hmm. I guess my attempt to parametrize was totally incorrect, my question now is how do I parametrize this problem?
 
z = √(7 - r2cos2θ - r2sin2θ)
s(r,θ) = (2cosθ, 2sinθ, √(7 - r2 (cos2θ - sin2θ)) )

0 < r < 2, 0 < θ < 2∏
 
Last edited:
Stan12 said:
z = √(7 - r2cos2θ - r2sin2θ)
r(r,θ) = (rcosθ, rsinθ, √(7 - r2 (cos2θ - sin2θ)) )
You're using the symbol, r, for two different things.

Are you saying that position vector, (x, y, z), is given by:
(x, y, z) = (rcosθ, rsinθ, √(7 - r2 (cos2θ - sin2θ)) )​
?

You need to restrict the values of r and θ .
 
I apologize for the bad notation, I found that 0 < r < 2 and 0 < θ < 2∏ as restriction
 
Ok. let me start from scratch, I'm going to set x = rcosθ , y = rsinθ and z = √(7 - (rcosθ)2 - (rsinθ)2), cylindrical coordinates.

I found the restriction to r by setting x2 + y2 = r2 in
portion of sphere given. which gives us r2 + z2 = 7

Now, it says that portion lies above a plane z = √3.
I plugged in z, r2 + (√3)2 = 7
and found that r = 2

and in cylindrical coordinates the restriction on θ = 2∏

Next, parametric of the portion, S(x,y) = (x, y, √(7 - x2 - y2))

Now, I'm stuck here. I'm unsure if this is correct approach in trying to parametrize.
 
Last edited:
After thinking this over, I believe that your position vector should be of the form: (r, θ, z) .

Writing x2 + y2 + z2 = 7 in cylindrical coordinates gives: r2 + z2 = 7.

Solve that for either r or z .
 
z = √7 - r2

s(x,y) = < x, y, (7 - x2 - y2)1/2

s(r,θ) = < rcosθ, rsinθ, (7 - (rcosθ)2 - (rsinθ)2)1/2
 
  • #10
What is sin2(θ) + cos2(θ) ?
 

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