MHB Partial DE-separation of variables

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The discussion focuses on solving the partial differential equation yux - 3x²uy = 0 using separation of variables. The user initially expresses confusion about deriving separable solutions and correctly identifies the form u = X(x)Y(y). They derive the equation y[X'/X] = 3x²[Y'/Y] and consider both positive and negative separation constants to form two ordinary differential equations. A suggestion is made to rearrange the equation to separate variables more clearly, allowing for easier solution of the ODEs. The user seeks confirmation that solving for both constants will yield all possible solutions to the PDE.
emily600
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Hi I'm having a bit of trouble with this question:

Use separation of variables to find all the possible separable solutions to the partial DE equation for u(x,y) given by
yux - 3x2 uy = 0
.I try u= X(x) Y(y)

ux = X'(x) Y(y)

uy = X(x) Y'
(y)

which gives y(X' Y)-3x2(X Y')

then I divide by (XY) and rearrange it into y[X'/X] = 3x2 [Y'/Y]

which is equal to the separationconstant K (I think)

y[X'/X] = 3x2 [Y'/Y] = Kand from here I get a bit lost. I try a positive constant, so I get two equations.

yX'/X = + K rearranged into {X'= XK/y}

3x2Y/Y = + K rearranged into {Y'= YK/3x2 }

and then I try a negative constant with more or less the same equations resulting, but I'm not sure what to do with them?

Is this how you find all the possible solutions of the pde (trying both a positive and a negative constant)?

I'm told I can check the solution by substitution but I'm not sure how. Any help would be really appreciated.

Thanks:confused::confused:.
 
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emily600 said:
Hi I'm having a bit of trouble with this question:

Use separation of variables to find all the possible separable solutions to the partial DE equation for u(x,y) given by
yux - 3x2 uy = 0
.I try u= X(x) Y(y)

ux = X'(x) Y(y)

uy = X(x) Y'
(y)

which gives y(X' Y)-3x2(X Y')

then I divide by (XY) and rearrange it into y[X'/X] = 3x2 [Y'/Y]

which is equal to the separationconstant K (I think)

y[X'/X] = 3x2 [Y'/Y] = K

You would do better to rearrange it as $\mathbf{\dfrac{X'}{x^2X}} = \mathbf{\dfrac{3Y'}{yY}}$. The left side is then purely a function of $\mathbf{x}$ and the right side is then purely a function of $\mathbf{y}.$ You are then justified in putting both sides equal to a separation constant, and you have two separate ODEs for $\mathbf{x}$ and $\mathbf{y}$.
 
Thanks that simplified things a little. For the positive constant I solved the 2 ODE's as:

View attachment 1591

And then put them together. If I do the same for a negative constant would that cover the possible solutions (assuming I can rearrange and solve them properly)?

Thanks:D
 

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