Partial derivatives and chain rule?

Click For Summary
SUMMARY

The discussion centers on calculating the second partial derivative Fxx of the function F(r,s,t,v) = r^2 + sv + t^3, where r = x^2 + y^2 + z^2, s = xyz, v = xe^y, and t = yz^2. Two methods for deriving Fxx are presented: the first uses the formula Fxx = Fxr.Rx + Fxs.Sx + Fxv.Vx + Fxt.Tx, while the second employs Fxx = Frx.Rx + Fr.Rxx + Fsx.Sx + Fs.Sxx + Fvx.Vx + Fv.Vxx. The correct approach involves expressing F in terms of x, y, z, and t, and differentiating accordingly, leading to the identification of calculation errors in the initial attempts.

PREREQUISITES
  • Understanding of partial derivatives
  • Familiarity with the chain rule in multivariable calculus
  • Knowledge of functions of multiple variables
  • Proficiency in differentiation techniques
NEXT STEPS
  • Study the application of the chain rule in multivariable calculus
  • Learn how to compute higher-order partial derivatives
  • Explore the implications of mixed partial derivatives
  • Review examples of differentiating composite functions
USEFUL FOR

Students and professionals in mathematics, engineering, and physics who require a solid understanding of multivariable calculus and its applications in solving complex derivative problems.

mohamed el teir
Messages
88
Reaction score
1
F(r,s,t,v) = r^2 + sv + t^3, where: r = x^2 +y^2+z^2 /// s = xyz /// v = xe^y /// t = yz^2
find Fxx
i have 2 solutions for this and i am not sure what is the right one
the first solution finds Fx then uses formula : Fxx = Fxr.Rx + Fxs.Sx + Fxv.Vx+Fxt.Tx
the 2nd solution find Fx then uses the formula : Fxx = Frx.Rx + Fr.Rxx + Fsx.Sx + Fs.Sxx + Fvx.Vx + Fv.Vxx = Frr.(Rx)^2+Fr.Rxx + Fss.(Sx)^2 + Fs.Sxx + Fvv.(Vx)^2 + Fv.Vxx
 
Physics news on Phys.org
mohamed el teir said:
F(r,s,t,v) = r^2 + sv + t^3, where: r = x^2 +y^2+z^2 /// s = xyz /// v = xe^y /// t = yz^2
find Fxx
i have 2 solutions for this and i am not sure what is the right one
the first solution finds Fx then uses formula : Fxx = Fxr.Rx + Fxs.Sx + Fxv.Vx+Fxt.Tx
the 2nd solution find Fx then uses the formula : Fxx = Frx.Rx + Fr.Rxx + Fsx.Sx + Fs.Sxx + Fvx.Vx + Fv.Vxx = Frr.(Rx)^2+Fr.Rxx + Fss.(Sx)^2 + Fs.Sxx + Fvv.(Vx)^2 + Fv.Vxx

It should be easy to figure out which one is correct. Just express ##F## in terms of ##x, y, z## and ##t## and differentiate.
 
PeroK said:
It should be easy to figure out which one is correct. Just express ##F## in terms of ##x, y, z## and ##t## and differentiate.
it was giving me a third answer at first but i discovered a mistake which i made in the calculations, i know the correct one now
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K