Partial Derivatives Maximum and Minimum Values

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To find the absolute maximum and minimum values of the function f(x,y) = 1 + 4x - 5y on the triangular region D with vertices (0,0), (2,0), and (0,3), it is necessary to first identify critical points by setting the partial derivatives fx and fy to zero. However, the calculations show that fx = 4 and fy = -5 do not yield any critical points, as these equations have no solutions. Therefore, the next step is to evaluate the function on the boundary of the triangular region D. The absolute maximum and minimum values will be determined from the extreme values found on this boundary. The absence of critical points indicates that the extrema must be located solely on the boundary of the defined region.
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Homework Statement


Find the absolute maximum and minimum values of f on
the set D.

f(x,y) = 1+4x-5y
D is the closed triangular region with vertices (0,0) (2,0) (0,3)

Homework Equations


To find the absolute maximum and minimum values of a continuous function
on a closed, bounded set :
1. Find the values of f at the critical points of f in D.
2. Find the extreme values of f on the boundary of D.
3. The largest of the values from steps 1 and 2 is the absolute maximum value;
the smallest of these values is the absolute minimum value.

The Attempt at a Solution



So I know to find the values of f at the critical points I must take partial fx and partial fy. Which both should be 0.

But fx(x,y) = 4 and fy(x,y) = -5. How do I set those equal to 0?
 
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As you have deduced those equations do not have solutions. That means that there are no critical points of f, so you must continue to step 2.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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