Partial derivatives; Tangent Planes

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SUMMARY

The discussion centers on calculating the slopes of the curves of intersection of the surface defined by the equation z = 2x²y at the point (1,1). The partial derivatives are computed as fx(x,y) = 4xy and fy(x,y) = 2x², yielding slopes of 4 and 2, respectively. A participant questions the correctness of these values, noting a discrepancy with another source that claims fx = 2 and fy = 4. The consensus is that the original calculations are correct, and the error lies in the alternate answer provided.

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JC3187
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Hi guys,

Question is:

Find the slopes of the curves of intersection of surface z = f(x,y) with the planes perpendicular to the x-axis and y-axis respectively at the given point.

z = 2x2y ...at (1,1).

fx(x,y) = 4xy ∴ Slope = 4
fy(x,y) = 2x2 ∴ Slope = 2

Is this wrong?

Answer has it the other way around fx = 2 and fy =4

what mistake did i make?

Thanks
 
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JC3187 said:
Hi guys,

Question is:

Find the slopes of the curves of intersection of surface z = f(x,y) with the planes perpendicular to the x-axis and y-axis respectively at the given point.

z = 2x2y ...at (1,1).

fx(x,y) = 4xy ∴ Slope = 4
fy(x,y) = 2x2 ∴ Slope = 2

Is this wrong?

Answer has it the other way around fx = 2 and fy =4

what mistake did i make?

Thanks
Your work looks fine. It looks like they switched the values in the "answer" you showed.
 
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I thought so too, thanks!
 

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