Partial derivatives with Wave Function

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abelanger
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Homework Statement


Knowing: y(x,t) = Acos(kx-ωt)
Find the partial derivatives of:
1) dy/dt
2) dy/dx
3) d^2y/dt^2
4) d^2y/dx^2

Homework Equations




The Attempt at a Solution


These are the answers the actual answers:
1) dy/dt = ωAsin(kx-ωt) = v(x,t) of a particle
2) dy/dx = -kAsin(kx-ωt)
3) d^2y/dt^2 = -(ω^2)Acos(kx-ωt) = a(x,t) of a particle
4) d^2y/dx^2 = -(k^2)Acos(ks-wt)

now here are my questions:
1) how come when I do the partial derivative of y with respect to t, kx becomes the constant and vice versa with dy/dx, how come ωt becomes the constant? is it because of implicit differentiation?
2) What does it give me to find: dy/dx? the slope? also what about d^2y/dx^2?

Thanks for the Help!
 
on Phys.org
abelanger said:
also what about d^2y/dx^2?

Thanks for the Help!

[tex] \dfrac{\partial ^{2}y}{\partial x^{2}}=\dfrac {1}{c^2}\dfrac{\partial ^{2}y}{\partial t^{2}}[/tex]
 
klondike said:
[tex] \dfrac{\partial ^{2}y}{\partial x^{2}}=\dfrac {1}{c^2}\dfrac{\partial ^{2}y}{\partial t^{2}}[/tex]

Ooooh.. Interesting!

Thanks