Partial Differentiation Problem

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Lucky mkhonza
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Hi to all,

I have been given the following problem as an assignment.

[tex]\frac{\partial ^2 \phi}{\partial \rho^2} + \frac{1}{\rho}\frac{\partial \phi}{\partial \rho} + \frac{1}{\rho^2}\frac{\partial \phi}{\partial \chi^2} + \frac{\partial ^2 \phi}{\partial Z^2}+B^2\phi = 0[/tex]

Here is my attempt to the problem:
Assuming [tex]\phi = S(\rho,\chi)Z(z)[/tex]

[tex]\frac{1}{S(\rho,\chi)}\frac{\partial ^2 S(\rho,\chi)}{\partial \rho^2} + \frac{1}{S(\rho,\chi) \rho }\frac{\partial S(\rho,\chi)}{\partial \rho} + \frac{1}{S(\rho,\chi) \rho^2}\frac{\partial S(\rho,\chi)}{\partial \chi^2} + \frac {1}{Z}\frac{\partial ^2 Z}{\partial Z^2} + B^2 = 0[/tex]

Separating the variables we get

[tex]\frac{\partial ^2 z}{\partial Z^2} + B^2 Z = 0[/tex]

[tex]\frac{1}{S(\rho,\chi)}\frac{\partial ^2 S(\rho,\chi)}{\partial \rho^2} + \frac{1}{S(\rho,\chi) \rho }\frac{\partial S(\rho,\chi)}{\partial \rho} + \frac{1}{S(\rho,\chi) \rho^2}\frac{\partial S(\rho,\chi)}{\partial \chi^2} + B^2 = 0[/tex]

Assuming [tex]S(\rho, \chi) = \rho(\rho) \chi(\chi)[/tex]

[tex]\frac{1}{\rho}\frac{\partial ^2 \rho}{\partial \rho^2} + \frac{1}{\rho^2 }\frac{\partial \rho}{\partial \rho} + \frac{1}{\rho^2 \chi}\frac{\partial ^2 \chi}{\partial \chi^2} + B^2 = 0[/tex]

How can I solve this last PDE?

Thank you in advance
 
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Okay, I haven't actually tried the problem, but you could try first to classify the pde (hyperbolic, elliptic, parabolic). In this case, the class of the pde depends on your choice of [tex]\rho[/tex]. Have you tried it?
 
[Hyperreality] Okay, I haven't actually tried the problem, but you could try first to classify the pde (hyperbolic, elliptic, parabolic). In this case, the class of the pde depends on your choice of [tex]\rho[/tex]
. Have you tried it? [/Q]

I don't know as to which class the PDE falls to. Let me state the whole problem so that it becomes clear to everyone.
Solve the following

[tex]\frac{\partial ^2 \phi}{\partial \rho^2} + \frac{1}{\rho}\frac{\partial \phi}{\partial \rho} + \frac{1}{\rho^2}\frac{\partial ^2 \phi}{\partial \chi^2} + \frac{\partial ^2 \phi}{\partial Z^2}+B^2\phi = 0[/tex]

Where: 0 < [tex]\rho[/tex] < R, 0 < [tex]\chi[/tex] < [tex]\pi[/tex], [tex]-\frac{H}{2} < z < \frac{H}{2}[/tex]

The Boundary Conditions are

[tex]\phi(R,\chi,z) = 0[/tex]
[tex]\phi(\rho,0,z) = \phi(\rho,\pi,z) = 0[/tex]
[tex]\phi(\rho,\chi, \pm \frac{H}{2}) = 0[/tex]


[Dr Transport] if you multiply by [tex]\rho^{2}[/tex] you'll be able to separate the variables completely. [/Q]

As you suggested to multiply the last PDE by [tex]\rho^{2}[/tex], when separating the PDE's involving both [tex]\rho[/tex] and [tex]\chi[/tex] I still have [tex]\rho^{2}[/tex] on one of the PDE's involving [tex]\chi[/tex]. See below

[tex]\frac{1}{\chi}\frac{\partial ^2 \chi}{\partial \chi^2} + B^2 \rho^2 = 0[/tex]

And

[tex]\rho \frac{\partial ^2 \rho}{\partial \rho^2} + \frac{\partial \rho}{\partial \rho} + B^2 \rho^2 = 0[/tex]
 
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