Partial Fraction Decomposition for (s^2+1)^2 - Homework Help

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Homework Statement


How to break down:
[tex]\frac{1}{(s^{2}+1)^{2}}[/tex]
into partial fractions?


Homework Equations


-


The Attempt at a Solution


I have tried:
[tex]\frac{1}{(s^{2}+1)^{2}} = \frac{1}{(1+i)^{2}\times(1-i)^{2}} = \frac{A}{(s+i)} + \frac{B}{(s+i)^{2}} + \frac{C}{(s-i)}} + \frac{D}{(s-i)^{2}}[/tex]

and

[tex]\frac{1}{(s^{2}+1)^{2}} = \frac{As+B}{(s^{2}+1)^{2}} + \frac{Cs+D}{(s^{2}+1)}[/tex]

and

[tex]\frac{1}{(s^{2}+1)^{2}} = \frac{As+B}{(s^{2}+1)} + \frac{Cs+D}{(s^{2}+1)}[/tex]

but none of them works..
Please help
 
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Hi v_bachtiar! :wink:

Why isn't 1/(s2 + 1)2) good enough as it is? :confused:

But if you do want to break it down further, your first try should have worked …

what did you get? :smile:
 
It is not good enough because I need to perform an inverse Laplace transform on the fraction.
And at my level, I only use tables and some basic theorems (convolution, shift in s etc.) and 1/(s2 + 1)2) is not on the table :(

I have attached my working using the first try..
 

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Hi v_bachtiar! :smile:

What makes you think A B C and D are real? :rolleyes:

Hint: to simplify it, what are 1/(s - i) ± 1/(s + i) and 1/(s - i)2 ± 1/(s + i)2 ? :wink:
 
They are 2s/(s2+1) or 0
and
(2s2-2)/(s2+1)2 or 4si/(s2+1)2

so..

(As-Ai+Cs+Ci) / (s2+1) + (B(s+i)2+D(s-i)2) / ((s2+1)2) = 1

and As-Ai+Cs+Ci = 2s , B(s+i)2+D(s-i)2 = 2s2-2

is this right?
 
oh, i mean:

(As-Ai+Cs+Ci) + (B(s+i)2+D(s-i)2) = 1
 
Hi v_bachtiar! :smile:

(just got up :zzz: …)
v_bachtiar said:
They are 2s/(s2+1) or 0
and …

No, 2s/(s2+1) or 2i/(s2+1) :redface:

ok, rewrite them as

(2s3+s)/(s2+1)2 or i(2s2+2)/(s2+1)2

Now can you see how to easily combine them with the others to get 1/(s2+1)2 ? :smile:
 
v_bachtiar said:

Homework Statement


How to break down:
[tex]\frac{1}{(s^{2}+1)^{2}}[/tex]
into partial fractions?


Homework Equations


-


The Attempt at a Solution


I have tried:
[tex]\frac{1}{(s^{2}+1)^{2}} = \frac{1}{(1+i)^{2}\times(1-i)^{2}} = \frac{A}{(s+i)} + \frac{B}{(s+i)^{2}} + \frac{C}{(s-i)}} + \frac{D}{(s-i)^{2}}[/tex]

and

[tex]\frac{1}{(s^{2}+1)^{2}} = \frac{As+B}{(s^{2}+1)^{2}} + \frac{Cs+D}{(s^{2}+1)}[/tex]

and

[tex]\frac{1}{(s^{2}+1)^{2}} = \frac{As+B}{(s^{2}+1)} + \frac{Cs+D}{(s^{2}+1)}[/tex]

but none of them works..
Please help
u can do as
A/s^2+1 + BX/(S^2+1)2
 
tiny-tim said:
Hi v_bachtiar! :smile:

(just got up :zzz: …)


No, 2s/(s2+1) or 2i/(s2+1) :redface:

ok, rewrite them as

(2s3+s)/(s2+1)2 or i(2s2+2)/(s2+1)2

Now can you see how to easily combine them with the others to get 1/(s2+1)2 ? :smile:


hi tiny-tim,

you mean combine (add) them with (2s2-2)/(s2+1)2?

so 1 = (2s3+s) + (2s2-2)

then, where do I imply the A, B, C, and D? :confused:

(thank you for your help so far) :smile:
 
How about (2s2+2) and (2s2-2) ? :wink: