Integrating (4x+1)^1/2 | Homework Help

In summary, the integration of (4x+1)^1/2 is (4x+1)^(3/2)/6, with a constant of integration. The actual answer is 3(4x+1)^(3/2)/8. To check for correctness, differentiate the result and compare with the initial expression.
  • #1
Priyadarshini
191
4

Homework Statement


Integrate (4x+1)^1/2

Homework Equations


Integration (ax+b)^n dx= (ax+b)^(n+1)/ a(n+1)

The Attempt at a Solution


(4x+1)^(3/2)/ 4(3/2)
= (4x+1)^(3/2)/6

but the actual answer is
3(4x+1)^(3/2)/8
 
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  • #2
Priyadarshini said:

Homework Statement


Integrate (4x+1)^1/2

Homework Equations


Integration (ax+b)^n dx= (ax+b)^(n+1)/ a(n+1)

The Attempt at a Solution


(4x+1)^(3/2)/ 4(3/2)
= (4x+1)^(3/2)/6

but the actual answer is
3(4x+1)^(3/2)/8
Take the derivative of your result and the correct result. Compare to help you see where you went awry .
 
  • #3
Priyadarshini said:

Homework Statement


Integrate (4x+1)^1/2

Homework Equations


Integration (ax+b)^n dx= (ax+b)^(n+1)/ a(n+1)

The Attempt at a Solution


(4x+1)^(3/2)/ 4(3/2)
= (4x+1)^(3/2)/6

but the actual answer is
3(4x+1)^(3/2)/8

No, the actual answer is what YOU obtained. Try differentiating your answer, to check if you get back your initial ##(4x+1)^{1/2}##.
 
  • #4
Priyadarshini said:

The Attempt at a Solution


(4x+1)^(3/2)/ 4(3/2)
= (4x+1)^(3/2)/6
Your result is correct. (but do not forget adding a C constant :smile:)
 
  • #5
Ray Vickson said:
No, the actual answer is what YOU obtained. Try differentiating your answer, to check if you get back your initial ##(4x+1)^{1/2}##.
It does. Thank you!
 
  • #6
ehild said:
Your result is correct. (but do not forget adding a C constant :smile:)
I keep forgetting to add the constant! Thanks!
 

Related to Integrating (4x+1)^1/2 | Homework Help

1. What is the process for integrating (4x+1)^1/2?

The process for integrating (4x+1)^1/2 is to first use the power rule to rewrite the expression as (4x+1)^1/2 = (4x+1)^0.5. Then, use the substitution method by letting u = 4x+1. This will give us the integral ∫(4x+1)^0.5 dx = ∫u^0.5 dx. Finally, use the power rule for integration and substitute back in the original variable u to get the final answer.

2. Can the integration of (4x+1)^1/2 be done using other methods?

Yes, besides the substitution method, the integration of (4x+1)^1/2 can also be done using the trigonometric substitution method or the integration by parts method. However, the most efficient and straightforward method is usually the substitution method.

3. Is there a specific range for the variable x when integrating (4x+1)^1/2?

No, there is no specific range for the variable x when integrating (4x+1)^1/2. The integration process remains the same regardless of the value of x.

4. Can the integration of (4x+1)^1/2 be simplified further?

Yes, depending on the context of the problem, the integral can be simplified further by using algebraic manipulation or trigonometric identities. However, the final answer will still involve the original expression (4x+1)^1/2.

5. What are some real-world applications of integrating (4x+1)^1/2?

The integration of (4x+1)^1/2 has various applications in physics, engineering, and economics. For example, it can be used to calculate the work done by a variable force, the distance traveled by a particle under a varying force, or the cost function in economics with changing prices.

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