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## Homework Statement

Find the partial fraction decomposition of :

[tex]\frac{x^2}{(1-x^4)^2}[/tex]

## The Attempt at a Solution

[tex]\frac{x^2}{(1-x^4)^2}=\frac{A}{(1-x^4)}+\frac {B}{(1-x^4)^2}[/tex]

[tex]=A(1-x^4)+B[/tex]

when x=1

[tex]1=A(1-1^4)+B[/tex]

Hence B=1 and A=0

[tex]\frac{x^2}{(1-x^4)^2}=\frac{0}{(1-x^4)}+ \frac{1}{(1-x^4)^2}[/tex]

How come according to the answers at the back of the book l am wrong. Where have l done a mistake ?