Partial Fractions - Solving Homework Equation with Coefficients

Click For Summary
SUMMARY

The discussion focuses on solving the partial fraction decomposition of the expression 1/((x^2-1)^2). The user attempts to express the function as (Ax+B)/(x^2-1) + (Cx+D)/((x^2-1)^2) and multiplies through by ((x^2-1)^2) to derive the equation 1=(Ax+B)(x^2-1)+ (Cx+D). Upon equating coefficients, the user finds A=0, B=0, C=0, and D=1, but encounters discrepancies when substituting back into the original equation, indicating a misunderstanding in the setup of the partial fractions.

PREREQUISITES
  • Understanding of partial fraction decomposition
  • Familiarity with polynomial multiplication and coefficient comparison
  • Knowledge of algebraic manipulation techniques
  • Basic calculus concepts related to limits and continuity
NEXT STEPS
  • Review the method of partial fraction decomposition in detail
  • Practice polynomial long division for complex fractions
  • Study the properties of rational functions and their asymptotic behavior
  • Explore examples of partial fractions with higher-order polynomials
USEFUL FOR

Students studying algebra, particularly those tackling calculus or advanced mathematics, as well as educators looking for examples of partial fraction decomposition techniques.

cragar
Messages
2,546
Reaction score
3

Homework Statement


1/((x^2-1)^2)


Homework Equations





The Attempt at a Solution


so i get (Ax+B)/(x^2-1) + (Cx+D)/((x^2-1)^2)

then i multiply both sides by ((x^2-1)^2)
then i get 1=(Ax+B)(x^2-1)+ (Cx+D)

then i multiply it out Ax^3+Bx^2 -Ax +Cx +D =1
then i equate the coeffcients
A=0 B=0 -A+C=0 -B+D=1 D=1

but when i plug these back in i don't get what my book gets and i setting this up correctly
 
Physics news on Phys.org
that should be
1/((x^2-1)^2)=A/(x+1)+B/(x+1)^2+C/(x-1)+D/(x-1)^2
 
ok i see
 

Similar threads

Replies
7
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 18 ·
Replies
18
Views
6K
  • · Replies 6 ·
Replies
6
Views
1K
Replies
9
Views
3K
  • · Replies 58 ·
2
Replies
58
Views
5K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
835
  • · Replies 4 ·
Replies
4
Views
2K