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Partial fractions with complex numb

  1. Jul 2, 2013 #1
    How do I turn 1/(x4+1) into partial fractions?

    This is what I did. Let me know if this is correct

    1/(x4+1) = 1/[(x^2+i)(x^2-i)] = (Ax+B)/(x2+i) + (Cx + D)/(x2-1)

    Then I set x = 0

    1 = (D-B)i .. My first equation would be D-B = 0.

    Is that correct so far?
     
    Last edited: Jul 2, 2013
  2. jcsd
  3. Jul 2, 2013 #2
    No need to use complex numbers. [itex] x^4+1=(x^2+1)^2-2x^2=(x^2+1+\sqrt{2}x)(x^2+1-\sqrt{2}x) [/itex]

    This is a very messy integral to do by hand, by the way.
     
    Last edited: Jul 2, 2013
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