Particle decaying into two daughter particles - special relativity

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SUMMARY

The discussion centers on the calculation of particle decay into two daughter particles within the framework of special relativity. The user initially miscalculates velocity, exceeding the speed of light, which is impossible according to relativity principles. The equations presented include momentum conservation, where the total momentum P is defined as P = (M, 0, 0, 0) and the individual momenta p1 and p2 are derived from energy and mass terms. The final velocity calculated is v = 8.90 x 10^16, which indicates a misunderstanding of relativistic effects.

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physconomics
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Homework Statement
A D meson decays into a K and pi-meson. Calculate energy and velocity of pi meson
Relevant Equations
E^2 = p^2c^2 + m^2c^4
Four vectors
rest mass of D = 1.86GEV/C^2
K = 0.5GEV/C^2
PI = 0.13GEV/C^2
Right, so I thought I'd done this correctly but clearly not because my velocity is greater than the speed of light, where have I gone wrong?

P = (M, 0, 0, 0)
p1 = (E1, p1x, p1y, p1z)
p2 = (E2, p2x, p2y, p2z)
P = p1 + p2
p2 = P - p1
square each side
to get (p2)2 = P2 - 2Pp1 + p12
therefore
(m2)2 = M2 - 2ME1 + m12
So E1 = (M2 - m12 + m22) / (2M)
which gives 0.867GeV

then
p1 = sqrt(E12 - m12) = 1.372x10^-10
then because p1=ymv, v = 8.90x10^16
where y = 0.867/0.13

Thank you!
 
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physconomics said:
p1 = sqrt(E12 - m12) = 1.372x10^-10
then because p1=ymv, v = 8.90x10^16
where y = 0.867/0.13
Can you explain this?
 

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