Particle in a box in cartesian coordinates

Click For Summary

Homework Help Overview

The discussion revolves around the Schrödinger equation for a particle in a three-dimensional box with boundaries defined by 0 to a in Cartesian coordinates. Participants explore the implications of separating variables in the equation and the conditions for energy levels in the system.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to understand if the second derivatives in the Schrödinger equation can be treated separately. Another participant questions whether the quantum numbers for the dimensions can be equal or different, linking this to the concept of degenerate energies. There are inquiries about the method for determining specific energy levels, particularly the 14th energy level, and discussions about the interpretation of energy levels in relation to sums of squares.

Discussion Status

Participants are actively engaging with the problem, raising questions about variable separation and energy level calculations. Some guidance has been provided regarding the relationship between spatial variables and time, but no consensus has been reached on the interpretation of energy levels or the methods for calculating them.

Contextual Notes

There is a mention of the complexity involved in finding energy levels and the specific interest in the 14th energy level, suggesting that there may be constraints or specific interpretations that are still under discussion.

gfd43tg
Gold Member
Messages
949
Reaction score
48

Homework Statement


upload_2015-5-13_14-52-38.png


Homework Equations

The Attempt at a Solution


a) The schrödinger equation
$$i \hbar \frac {\partial \Psi}{\partial t} = - \frac {\hbar^{2}}{2m} \nabla^{2} \psi + V \psi $$
For the case ##0 \le x,y,z \le a##, ##V = 0##
$$i \hbar \frac {\partial \Psi}{\partial t} = - \frac {\hbar^{2}}{2m} \Big [ \frac {\partial^{2} \psi}{\partial x^{2}} + \frac {\partial^{2} \psi}{\partial y^{2}}+ \frac {\partial^{2} \psi}{\partial z^{2}} \Big ]$$
But with the sum of the second derivates, is it possible to set each of these equal to the time derivative separately? If so, then why?
 
Physics news on Phys.org
ImageUploadedByPhysics Forums1431503226.695426.jpg
ImageUploadedByPhysics Forums1431503246.977950.jpg


Okay I have made some progress on this problem, however I am curious, is it the case that ##n_{x} = n_{y} = n_{z}##? If they are allowed to be different numbers, I suspect that is what allows for degenerate energies.
 
Last edited:
Re your first question. If you have separate functions of each variable, then consider holding every spatial variable constant. This shows that the time function must be constant. In general:

##T(t) = F(x, y, z) \ \Rightarrow \ T(t) = C = F(x, y, z)##

And:

##X(x) + Y(y) + Z(z) = C \ \Rightarrow \ X(x) = C_x, \ Y(y) = C_y, \ Z(z) = C_z## where ##C_x + C_y + C_z = C##

But, there's no reason that ##C_x = C_y = C_z = C/3##
 
Is there any easy way to find a given ##E_{n}##? Or do you need to do every combination to get ##E_{14}##?
 
Not too many possibilities to get 14 as the sum of three squares ...
 
That is not what is meant by ##E_{14}##, they mean the 14th highest energy level. Not that the sum of the squares is 14
 
From the problem statement wording I'm inclined to say you are right.
Usually, we call them EN with EN = N E0 -- so I got sidetracked.

But then why Griffiths thinks E14 is so interesting is a mystery to me. Let us know if you find something !
 
Maylis said:
Is there any easy way to find a given ##E_{n}##? Or do you need to do every combination to get ##E_{14}##?

There's a whole sequence here of the number of ways that each integer can be expressed as a sum of 3 non-zero squares:

https://oeis.org/A025427

https://oeis.org/A025427/b025427.txt

For example:

66 is the first integer that can be expressed in 3 different ways; 129 in 4 different ways; 194 in 5 different ways; 209 in 6 ways.
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 30 ·
2
Replies
30
Views
4K
Replies
29
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 8 ·
Replies
8
Views
5K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 19 ·
Replies
19
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K