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Particle in a box in cartesian coordinates

  • Thread starter gfd43tg
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  • #1
gfd43tg
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Homework Statement


upload_2015-5-13_14-52-38.png


Homework Equations




The Attempt at a Solution


a) The schrödinger equation
$$i \hbar \frac {\partial \Psi}{\partial t} = - \frac {\hbar^{2}}{2m} \nabla^{2} \psi + V \psi $$
For the case ##0 \le x,y,z \le a##, ##V = 0##
$$i \hbar \frac {\partial \Psi}{\partial t} = - \frac {\hbar^{2}}{2m} \Big [ \frac {\partial^{2} \psi}{\partial x^{2}} + \frac {\partial^{2} \psi}{\partial y^{2}}+ \frac {\partial^{2} \psi}{\partial z^{2}} \Big ]$$
But with the sum of the second derivates, is it possible to set each of these equal to the time derivative separately? If so, then why?
 

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  • #2
gfd43tg
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ImageUploadedByPhysics Forums1431503226.695426.jpg
ImageUploadedByPhysics Forums1431503246.977950.jpg


Okay I have made some progress on this problem, however I am curious, is it the case that ##n_{x} = n_{y} = n_{z}##? If they are allowed to be different numbers, I suspect that is what allows for degenerate energies.
 
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  • #3
PeroK
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Re your first question. If you have separate functions of each variable, then consider holding every spatial variable constant. This shows that the time function must be constant. In general:

##T(t) = F(x, y, z) \ \Rightarrow \ T(t) = C = F(x, y, z)##

And:

##X(x) + Y(y) + Z(z) = C \ \Rightarrow \ X(x) = C_x, \ Y(y) = C_y, \ Z(z) = C_z## where ##C_x + C_y + C_z = C##

But, there's no reason that ##C_x = C_y = C_z = C/3##
 
  • #4
gfd43tg
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Is there any easy way to find a given ##E_{n}##? Or do you need to do every combination to get ##E_{14}##?
 
  • #5
BvU
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Not too many possibilities to get 14 as the sum of three squares ...
 
  • #6
gfd43tg
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That is not what is meant by ##E_{14}##, they mean the 14th highest energy level. Not that the sum of the squares is 14
 
  • #7
BvU
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From the problem statement wording I'm inclined to say you are right.
Usually, we call them EN with EN = N E0 -- so I got sidetracked.

But then why Griffiths thinks E14 is so interesting is a mystery to me. Let us know if you find something !
 
  • #8
PeroK
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Is there any easy way to find a given ##E_{n}##? Or do you need to do every combination to get ##E_{14}##?
There's a whole sequence here of the number of ways that each integer can be expressed as a sum of 3 non-zero squares:

https://oeis.org/A025427

https://oeis.org/A025427/b025427.txt

For example:

66 is the first integer that can be expressed in 3 different ways; 129 in 4 different ways; 194 in 5 different ways; 209 in 6 ways.
 

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