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Particle in a magnetic field - x,y,z components

  1. Mar 21, 2010 #1
    1. The problem statement, all variables and given/known data

    A particle with charge 2.8 C moves through a uniform magnetic field. At one instant the velocity of the particle is (1.4 i + 1.2 j + 0.48 k) m/s and the magnetic force on the particle is (11.9 i - 14.1 j + 1.57 k) N. The x and y components of the magnetic field are equal. What are (a) the x-component, (b) the y-component, and (c) the z-component of the magnetic field?

    2. Relevant equations

    F=q(v X B)

    3. The attempt at a solution

    I have tried this twice and cannot figure out this solutions. Can someone please point be in the right direction?
  2. jcsd
  3. Mar 21, 2010 #2


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    Homework Helper

    If the vector B is B=Bxi+Byj+Bzk

    What is q(vxB) equal to? (Write this in the vector form)

    Since they gave you what F is, and you just calculated q(vxB) (which is F), equate components.
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