Particle in an infinite potential box- expected values of energy

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Homework Help Overview

The discussion revolves around a quantum mechanics problem involving a particle in an infinite potential box, specifically focusing on the expected values of energy and probabilities associated with different quantum states. The original poster presents a wavefunction and poses questions regarding the calculation of expected energy values and probabilities of finding the particle in specific states.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculation of expected energy values and the interpretation of momentum in the context of the uncertainty principle. There are attempts to clarify the limits of integrals and the definitions of various quantities such as momentum and uncertainties. Questions arise regarding the correctness of the wavefunction and its relation to energy eigenstates.

Discussion Status

The discussion is ongoing, with participants providing guidance on the correct approach to calculating probabilities and expected values. There is recognition of the need to use the correct wavefunctions for calculations, and some participants express confusion about the results obtained, particularly in relation to expected forms of energy and probabilities.

Contextual Notes

Participants note that the wavefunction provided does not correspond to an energy eigenstate, which may affect the expected results. There is also mention of the potential need to revisit the definitions and calculations related to uncertainties and expectation values.

  • #31
Could anybody please respond?
 
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  • #32
Hello, Rorshach. I don't understand "by leveraging development coefficients" in part (c), so I don't think I can help much.

You've already calculated ##<\hat{p}^2>##, so once you determine ##<p>## you will easily be able to get ##\Delta p##.

Note that the wavefunction ##\psi## is an even function about ##x = a/2##. Since ##\hat{p}## is proportional to the derivative operator, you should be able to argue that ##\hat{p} \psi## is an odd function about ##x = a/2##. So, if you set up the integral for ##<\hat{p}>## you should be able to conclude what the answer is without actually carrying out the integration. But that doesn't appear to be the way you are expected to do it.

I will bring this problem to the attention of some of the other helpers.

I guess you don't have access to the person who made the question. It would be nice if you could get clarification on what he/she meant for you do do here.
 
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  • #33
Unfortunately, I have no contact with the person who made this question. I also don't want to integrate anything, since it was clearly stated in the problem to not to do it, however user tannerbk gave a formula a few replies above for expectated value for hamiltonian <H>, so maybe there is an analogic one for <p>?
 
  • #34
Maybe they want something like this. You know that you can expand your wave function in terms of the energy eigenstates:

##\psi(x) = \sum c_n \sin(k_n x)## where ##k_n = n\pi/a##.

Write each ##\sin(k_n x)## as ##\frac{1}{2i}(e^{ik_nx} - e^{-ik_nx})##.

Suppose you could show that each exponential ##e^{ik_nx}## is a momentum eigenstate corresponding to momentum ##\hbar k_n## while each exponential ##e^{-ik_nx}## is a momentum eigenstate corresponding to momentum ##-\hbar k_n##.

Can you then construct an argument showing ##<\hat{p}> = 0##?

Note, however, that this type of argument might not be sound. There are difficulties with defining a momentum operator for the particle in a box. The functions ##e^{ik_nx}## don't satisfy the boundary conditions of the particle in a box, so I'm not sure they qualify as legitimate states for the particle in a box.

See for example http://academic.reed.edu/physics/fa...ous Essays/Generalized Momentum Operators.pdf

or this thread https://www.physicsforums.com/showthread.php?t=285694
 
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