Particle in an infinite potential box- expected values of energy

  • #31
Could anybody please respond?
 
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  • #32
Hello, Rorshach. I don't understand "by leveraging development coefficients" in part (c), so I don't think I can help much.

You've already calculated ##<\hat{p}^2>##, so once you determine ##<p>## you will easily be able to get ##\Delta p##.

Note that the wavefunction ##\psi## is an even function about ##x = a/2##. Since ##\hat{p}## is proportional to the derivative operator, you should be able to argue that ##\hat{p} \psi## is an odd function about ##x = a/2##. So, if you set up the integral for ##<\hat{p}>## you should be able to conclude what the answer is without actually carrying out the integration. But that doesn't appear to be the way you are expected to do it.

I will bring this problem to the attention of some of the other helpers.

I guess you don't have access to the person who made the question. It would be nice if you could get clarification on what he/she meant for you do do here.
 
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  • #33
Unfortunately, I have no contact with the person who made this question. I also don't want to integrate anything, since it was clearly stated in the problem to not to do it, however user tannerbk gave a formula a few replies above for expectated value for hamiltonian <H>, so maybe there is an analogic one for <p>?
 
  • #34
Maybe they want something like this. You know that you can expand your wave function in terms of the energy eigenstates:

##\psi(x) = \sum c_n \sin(k_n x)## where ##k_n = n\pi/a##.

Write each ##\sin(k_n x)## as ##\frac{1}{2i}(e^{ik_nx} - e^{-ik_nx})##.

Suppose you could show that each exponential ##e^{ik_nx}## is a momentum eigenstate corresponding to momentum ##\hbar k_n## while each exponential ##e^{-ik_nx}## is a momentum eigenstate corresponding to momentum ##-\hbar k_n##.

Can you then construct an argument showing ##<\hat{p}> = 0##?

Note, however, that this type of argument might not be sound. There are difficulties with defining a momentum operator for the particle in a box. The functions ##e^{ik_nx}## don't satisfy the boundary conditions of the particle in a box, so I'm not sure they qualify as legitimate states for the particle in a box.

See for example http://academic.reed.edu/physics/fa...ous Essays/Generalized Momentum Operators.pdf

or this thread https://www.physicsforums.com/showthread.php?t=285694
 
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