Particle in gravitational field

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SUMMARY

The discussion focuses on a particle of mass m constrained to move on the surface of a paraboloid defined by the equation r²=4az, subjected to gravitational force. The frequency of small oscillations around a circular orbit with radius ρ=√4az₀ is derived as ω=√(2g/(a+z₀)). Participants clarify that the term "oscillating" refers to the particle's motion around a horizontal circle at height z₀, and suggest using Newton's second law to determine angular velocity and frequency.

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Math Jeans
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Homework Statement



Consider a particle of mass m constrained to move on the surface of a paraboloid whose equation (in cylindrical coordinates) is [tex]r^2=4az[/tex]. If the particle is subject to a gravitational force, show that the frequency of small oscillations about a circular orbit with radius [tex]\rho=\sqrt{4az_0}[/tex] is

[tex]\omega=\sqrt{\frac{2g}{a+z_0}}[/tex]

Homework Equations





The Attempt at a Solution



The problem that I'm having is that I don't understand the wording of the question?

How do I draw out this scenario?
 
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Math Jeans said:
Consider a particle of mass m constrained to move on the surface of a paraboloid whose equation (in cylindrical coordinates) is [tex]r^2=4az[/tex]. If the particle is subject to a gravitational force, show that the frequency of small oscillations about a circular orbit with radius [tex]\rho=\sqrt{4az_0}[/tex] is

[tex]\omega=\sqrt{\frac{2g}{a+z_0}}[/tex]

Hi Math Jeans! :smile:

It means that the ball is freely rotating (I don't know why they call it oscillating) around a horizontal circle at height z0 (so the radius is √4az0).

I think the word "small" means that you can pretend that eg sinx = x.

Use Newton's second law to find the angular velocity, and therefore the frequency of the rotation. :smile:
 

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