Particle Motion: Retardation & Arithmetic Progression

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Homework Help Overview

The problem involves a particle moving in a straight line with its speed defined as inversely proportional to its distance from a fixed point. The discussion centers around finding the retardation of the particle and demonstrating that the times taken to travel equal distances increase in arithmetic progression.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss how to find the retardation, suggesting the use of the chain rule to express acceleration in terms of velocity and distance. There are attempts to set up the problem using specific coordinates for the points involved.

Discussion Status

Some participants are actively questioning how to derive the retardation and are exploring the relationship between distance and time for the successive segments. Hints have been provided regarding the use of the chain rule, but no consensus or resolution has been reached yet.

Contextual Notes

Participants express uncertainty about the application of the chain rule and the setup of the problem, indicating potential gaps in understanding the relationships between variables.

Cbray
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Homework Statement


A particle moves in a straight line away from a fixed point O in the line, such that when its distance from O is x its speed v is given by v=k/x , for some constant k.

(a) show that the particle has a retardation which is inversely proportional to x3
The answer is -k2*x-3

(b) if a,b,c,d are points in that order on the straight line, such that the distances ab, bc, cd are all equal, show that the times taken to travel these successive distances increase in arithmetic progression.

Homework Equations


Possible the answer to the first one comes into relevance, -k2*x-3


The Attempt at a Solution


let the four points have x coordinates
x, x+xo , x+2xo , x+3xo
 
Last edited:
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For part a) how would you find the retardation ? (negative acceleration)

(Hint: use the chain rule to express 'a' in terms of 'v' and 'x')

For part b) try finding time based on t= distance/velocity at the given points.
 
rock.freak667 said:
For part a) how would you find the retardation ? (negative acceleration)

(Hint: use the chain rule to express 'a' in terms of 'v' and 'x')

For part b) try finding time based on t= distance/velocity at the given points.

I still can't figure it out :L
 
Cbray said:
I still can't figure it out :L

If a=dv/dt, can you use the chain rule to re-write this in terms of v and x? (Hint: you will have to have a dv/dx term)
 

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