1. A particle moving at a velocity of 6.5 m/s in the positive x direction is given an acceleration of 0.9 m/s^2 in the positive y direction for 2.9 s. What is the final speed of the particle? 2. Relevant equations v= vi +at 3. The attempt at a solution v= 6.5 + (.9)(2.9)= 9.11 m/s I don't know if the velocity is right. the velocity is horizontal, and acceleration is vertical, so it makes me doubt.