Pascal's Principle Calculations

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SUMMARY

This discussion focuses on the application of Pascal's Principle in hydraulic systems, specifically using the formula f/a = F/A to calculate forces exerted by pistons of different sizes. The user successfully calculated that the larger piston can sustain a force F equal to f multiplied by 195, confirming the relationship between the small and large pistons. Additionally, for the second calculation involving a 20.0 kN force on the large piston, the user determined that the force magnitude on the small piston is 102 N. The calculations align with the principles of hydraulics and the provided dimensions of the pistons.

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A piston of cross-sectional area "a" is used in a hydraulic press to exert a small force of magnitude "f" on the enclosed liquid. A connecting pipe leads to a larger piston of cross-sectional area A. (a) what force magnitude F will the larger piston sustain without moving? (b) If the piston diameters are 3.80 cm and 53.0 cm, what force magnitude on the small piston will balance a 20.0 kN force on the large piston?

A picture of the figure can be found at
http://panda.unm.edu/Courses/Price/Phys160/F33-3.jpeg

I used the formula f/a = F/A for (a). the answer I found was F = f x 195. Am i supposed to leave f in my answer. If no, how do i solve for f.

I used the same formula for (b) and got 102.

Please help me double check my answers.
 
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Seems to be correct. In the first Q, you just have to write fA/a, I think, because the values are given only in (b).
 
Thanks for the help.
 

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