Pathline and Streamline problem

  • Thread starter Thread starter Abigail1997
  • Start date Start date
  • Tags Tags
    Streamline
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
4 replies · 2K views
Abigail1997
Messages
6
Reaction score
0
Screen Shot 2016-07-27 at 17.55.55.png
1. Homework Statement

As above

Homework Equations


Not sure.

The Attempt at a Solution


I've only ever seen one of these problems and it was in the form of V=Axi-Ayj, so much simpler and even then it was poorly explained by the lecturer. I understand what a velocity field is but not much more.
 
Physics news on Phys.org
statement, all variables and given/known data
I have completed question a, getting e^(t+((t^2)/4)) and e^t respectively and found the streamline for t=0, getting x=Cy, c being a constant- but am totally out of idea for finding it when t=1. I have been told the answer is e^3/2 but not sure how to get there

Homework Equations


dx/u=dy/v[/B]
first paragraph counts as an attempt at solution, I would say. (Choosing C as parameter is unfortunate, though, if the problem statement already has a C.)
Can't guess what u and v are; the components of ##\vec v## ?
You found the streamlines at t =0 from ##\vec v = Bx\hat\imath + Cy\hat\jmath##
Aren't the streamlines for t=1 given by simply substituting t=1 and doing the same thing ?
 
  • Like
Likes   Reactions: Abigail1997
BvU said:
first paragraph counts as an attempt at solution, I would say. (Choosing C as parameter is unfortunate, though, if the problem statement already has a C.)
Can't guess what u and v are; the components of ##\vec v## ?
You found the streamlines at t =0 from ##\vec v = Bx\hat\imath + Cy\hat\jmath##
Aren't the streamlines for t=1 given by simply substituting t=1 and doing the same thing ?

Yeah I realized that and changed it to D :) correct, u and v represent the x and y components of V. As for the subbing in t=1, that's what I thought but I cannot seem to get the correct answer (e^3/2) but I'm probably making a silly mistake somewhere and just can't see it
 
Check the non-moving dashes in the first picture here (watch out for headaches).
These dashes at fixed grid points you can draw for t=1 in your exercise. They should suggest the ##e^{3\over 2}##
 
  • Like
Likes   Reactions: Abigail1997