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axe34

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## Homework Statement

I am trying to understand a problem that I made for myself (although this is based on other problems I've encountered).

We have a tank (reservoir) 2.9534 m in height and a head loss of 2.88 m from beginning to end; the loss is due to friction etc. There is discharge to atmosphere; see diagram 1 below

The velocity of water at the exit is found via bernoulli's equations:

V1^2/2g + Z1 + p1/rho.g - losses =

**V2^2/2g + Z2 + p2/rho.g**

With respect to a streamline from the top of the reservoir to the exit of the pipe, I get V2 as 1.2 m/s (with V1 = 0, Z1 = 2.9534, losses = 2.88, Z2 = 0 and p1 and p2 = atmospheric pressure).

With respect to diagram 2,

*I always thought that head loss at any point was 2.9534 - H*. Say I move this piezometer to the right hand side with H = 2.88 m then I get the same velocity as before using bernoulli equations. Why? This isn't the definition of head loss?

## Homework Equations

As above

## The Attempt at a Solution

As above