Pdf of area and circumference of a circle

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SUMMARY

The discussion focuses on determining the probability density function (p.d.f.) of the area and circumference of a circle given a random variable radius X with a specified p.d.f. of f(x) = (1/8)(3x + 1) for 0 < x < 2. The area is calculated using the formula Area = πr², and the circumference is calculated using Circumference = 2πr. The participants suggest substituting the p.d.f. of the radius into these equations to derive the respective p.d.f.s for area and circumference.

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  • Understanding of probability density functions (p.d.f.)
  • Knowledge of basic geometry formulas for area and circumference
  • Familiarity with calculus concepts, particularly integration
  • Experience with random variables and transformations
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Homework Statement


Suppose that the radius X of a circle is a random variable having the following p.d.f.:
f(x)={ (1/8)(3x=1) for 0<x<2
0 otherwise
Determine the p.d.f. of the area of the circle and the circumference of the circle.

Homework Equations


Area=[tex]\Pi[/tex]r2
Circumference=2[tex]\Pi[/tex]r

The Attempt at a Solution


can i just insert f(x) in for r in both equations to generate the pdf??
meaning...
if g is the area of the circle with r=f(x)
g(f(x))={[tex]\Pi[/tex][(1/8)(3x+1)]2 for 0<x<2
0 otherwise
likewise for circumference
 
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no, they will be related by
[tex]|f(r)dr| = |f(c)dc|[/tex]

where c is circumference & the change dc correspond to the incremental dr
 

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