Pendulem in an Accelerting Plane

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SUMMARY

The discussion focuses on calculating the acceleration of a jet plane using a pendulum with a length of 1.14 m that oscillates due to the plane's uniform acceleration. The pendulum's displacement from the equilibrium position is 0.42 m. The key takeaway is that the acceleration of the plane can be determined through vector addition of forces acting on the pendulum, emphasizing the importance of understanding both velocity and acceleration as vector quantities.

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  • Understanding of pendulum dynamics and oscillation principles
  • Knowledge of vector addition in physics
  • Familiarity with basic kinematics
  • Concept of equilibrium in oscillatory motion
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A pendulum has a length L = 1.14 m. It hangs straight down in a jet plane about to take off as shown by the dotted line in the figure. The jet accelerates uniformly, and during that time, the pendulum oscillates about the equilibrium position shown by the solid line, with D = 0.42 m. What is the acceleration of the plane?
 

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BrettL789123 said:
A pendulum has a length L = 1.14 m. It hangs straight down in a jet plane about to take off as shown by the dotted line in the figure. The jet accelerates uniformly, and during that time, the pendulum oscillates about the equilibrium position shown by the solid line, with D = 0.42 m. What is the acceleration of the plane?

HI BrettL789123! :smile:

(ignore the fact that it's a pendulum. … only the angle of the equilibrium position matters :smile:)

This is a vector addition problem.

I expect you're used to velocites adding like vectors.

Well, accelerations do also! :biggrin:
 

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