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Homework Help: Pendulum clock question

  1. Sep 8, 2004 #1
    I am trying to solve this question..

    A pendulum clock with a pendulum made of brass is designed to keep accurate time at 23 °C. If the clock operates at 0.0°C, what is the magnitude of its error, in seconds per hour (use a minus sign to indicate slowing down)? The linear expansion coefficient of brass is 19 x 10-6 /C°.

    I know that the the period of oscillation is

    T= 2pi * sqrt( L /g)

    and that the change in the length of the pendulum

    -4.37E-4 m

    I just don't know how to relate the two to solve
    Any help is appreciated.
  2. jcsd
  3. Sep 8, 2004 #2


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    Because T varies as the square root of L the relative errors are related by
    [tex]\frac {\delta T}{T} = \frac {1}{2} \frac {\delta L}{L}[/tex]
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