Percentage energy loss (mechanical energy) problem

Click For Summary

Homework Help Overview

The problem involves calculating the percentage energy loss of an object sliding down a low-friction incline, with specific measurements of mass, height, and speed at different points during its motion.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the original poster's attempt to apply energy conservation principles and question the calculations involved. There are suggestions to clarify the conversion to percentage and to isolate the work done by other forces.

Discussion Status

The discussion is ongoing, with participants providing feedback on the original approach and emphasizing the need for detailed calculations. There is no explicit consensus, but several participants are guiding the original poster towards refining their method.

Contextual Notes

Participants note potential issues with the calculations and the interpretation of energy loss, as well as the importance of showing all steps in the reasoning process.

poopandpee
Messages
1
Reaction score
0

Homework Statement


Problem: An object with mass 2.0 kg slides down a low-friction incline and its speed measured at the bottom is 2.7 m/s. The object starts sliding at a height of 0.50 m over the tabletop and its speed is measured 0.10 m over the tabletop. How big is the percentage energy loss?

Homework Equations

The Attempt at a Solution


My attempt: I've tried using this formula: mgh(0) + W(other forces) = 0.5mv2, where m=2.0 kg, h=0.4 m, and v=2.7 Then I found W(other forces) and divided it by mgh(0). However, that did not give a right answer. Any suggestions?
 
Physics news on Phys.org
The sign of the energy loss is a bit questionable but overall the approach is good. Maybe some mistake in the calculations? You didn't show them.
 
Did you remember to multiply by 100 to convert to %?
 
You shouldn't divide by the other work, if your equation above is correct you should subtract mgh(0) to get W alone
 
NateTheGreatt77 said:
You shouldn't divide by the other work, if your equation above is correct you should subtract mgh(0) to get W alone
That appears to be what @poopandpee did before dividing:
poopandpee said:
Then I found W(other forces)
As others have posted, the method sounds correct, but we need to see the details.
 

Similar threads

Replies
6
Views
2K
Replies
10
Views
5K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 3 ·
Replies
3
Views
5K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 5 ·
Replies
5
Views
5K
Replies
9
Views
5K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K