Performance data of a car owned by a student....

Click For Summary
The discussion centers on the correct formulation of the equation for the position of a car as a function of time during a specific phase of motion. The initial equation presented, x = 50t - 375, is questioned for its accuracy. It is clarified that the correct form should be x = 375 + 50Δt, where Δt represents the time elapsed since reaching point a. The values of x and t at point a do not satisfy the original equation but do satisfy the corrected version. Understanding the distinction between elapsed time since the start of motion and since reaching point a is crucial for accurate equation formulation.
Alexanddros81
Messages
177
Reaction score
4
Homework Statement
Serway Physics Problem 2.43

Figure P2.43 represents part of the performance data f a car owned by a proud physics student. (a) Calculate the total distance traveled by computing the area under the red-brown graph line. (b) What distance does the car travel between the times t=10s and t=40s?
(c) Draw a graph of its acceleration versus time between t=0 and t=50s
(d) Write an equation for x as a function f time for each phase of the motion , represented by the segments 0a, ab, and bc.
(e) What is the average velocity of the car between t=0and t=50s?
Relevant Equations
See at solution
Figure P2_43.jpg


Serway P2_43001.jpg


Serway P2_43002.jpg


Hi. My question is for now why the equation of x as a function of time for phase of motion ab is ##x=50t-375##?
Shouldn't that be ##x=375+50t##?
 
Physics news on Phys.org
Alexanddros81 said:
Hi. My question is for now why the equation of x as a function of time for phase of motion ab is ##x=50t-375##?
Shouldn't that be ##x=375+50t##?
What are the values of ##x## and ##t## at point ##a##? Do these values satisfy your equation?
 
At point a the value of x=375m and value of t=15s.
These values don't satisfy my equation.
But they satisfy the equation ##x=50t-375##.
 
Alexanddros81 said:
At point a the value of x=375m and value of t=15s.
These values don't satisfy my equation.
But they satisfy the equation ##x=50t-375##.
Right. Can you see why your equation is not correct?
 
Right. Can you see why your equation is not correct?
No. Can you explain?
 
Keep in mind that the symbol ##t## denotes the time that has elapsed since the beginning of the motion, not the time that has elapsed since reaching point ##a##. Your equation would be correct if written in the form

x = 375 + 50##\Delta t##

where ##\Delta t## is the time elapsed since reaching point ##a##.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 2 ·
Replies
2
Views
11K
  • · Replies 30 ·
2
Replies
30
Views
3K
Replies
5
Views
2K
  • · Replies 23 ·
Replies
23
Views
5K
Replies
25
Views
1K
  • · Replies 20 ·
Replies
20
Views
7K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
7K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 4 ·
Replies
4
Views
4K