Performance data of a car owned by a student....

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SUMMARY

The discussion centers on the correct formulation of the equation of motion for a car, specifically the equation of x as a function of time during phase ab. The correct equation is identified as x = 50t - 375, which accurately reflects the position at time t. The values at point a, where x = 375m and t = 15s, satisfy this equation, confirming its validity. The incorrect formulation suggested was x = 375 + 50t, which does not hold true for the given values.

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Alexanddros81
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Homework Statement
Serway Physics Problem 2.43

Figure P2.43 represents part of the performance data f a car owned by a proud physics student. (a) Calculate the total distance traveled by computing the area under the red-brown graph line. (b) What distance does the car travel between the times t=10s and t=40s?
(c) Draw a graph of its acceleration versus time between t=0 and t=50s
(d) Write an equation for x as a function f time for each phase of the motion , represented by the segments 0a, ab, and bc.
(e) What is the average velocity of the car between t=0and t=50s?
Relevant Equations
See at solution
Figure P2_43.jpg


Serway P2_43001.jpg


Serway P2_43002.jpg


Hi. My question is for now why the equation of x as a function of time for phase of motion ab is ##x=50t-375##?
Shouldn't that be ##x=375+50t##?
 
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Alexanddros81 said:
Hi. My question is for now why the equation of x as a function of time for phase of motion ab is ##x=50t-375##?
Shouldn't that be ##x=375+50t##?
What are the values of ##x## and ##t## at point ##a##? Do these values satisfy your equation?
 
At point a the value of x=375m and value of t=15s.
These values don't satisfy my equation.
But they satisfy the equation ##x=50t-375##.
 
Alexanddros81 said:
At point a the value of x=375m and value of t=15s.
These values don't satisfy my equation.
But they satisfy the equation ##x=50t-375##.
Right. Can you see why your equation is not correct?
 
Right. Can you see why your equation is not correct?
No. Can you explain?
 
Keep in mind that the symbol ##t## denotes the time that has elapsed since the beginning of the motion, not the time that has elapsed since reaching point ##a##. Your equation would be correct if written in the form

x = 375 + 50##\Delta t##

where ##\Delta t## is the time elapsed since reaching point ##a##.
 

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