Period of a Pendulum: Calculate New Period & 24h Loss

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Homework Help Overview

The discussion revolves around the calculation of the period of a pendulum and the time loss of a clock using this pendulum over a 24-hour period, with specific values for gravitational acceleration (g). The original poster presents a scenario involving a pendulum with a known period and seeks to determine how changes in g affect the period and the clock's accuracy.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate the new period of the pendulum with a different gravitational acceleration and questions how to determine the time lost over 24 hours. Some participants inquire about the reasoning behind the calculations and the implications of the results. Others suggest reconsidering the approach to ensure understanding rather than just providing answers.

Discussion Status

The discussion includes various interpretations of the calculations and the implications of the results. Some participants express concern about the effectiveness of simply providing answers without fostering understanding. There is acknowledgment of differing views on how to best assist the original poster in grasping the concepts involved.

Contextual Notes

Participants note the importance of adhering to forum rules regarding guidance and the sharing of information. There is mention of a potential error in the data used for calculations, which may affect the discussion.

jdeakons
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A clock pendulum has a period of 1.222 seconds where g = 9.812 m/s^2.

1. What is the new period of the pendulum when g = 9.797 m/s^2?

2. How many seconds will a clock using this pendulum lose in 24 hours?

For the first one, using 7 significant figures, the new period comes out to 1.222935 seconds. I'm not sure how to do the second part. Any suggestions?

Thanks.
 
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Thanks for the post, but how did you arrive at the resulting numbers? I also don't understand how .102 seconds are lost for every 1 second...
 
...start with the equation for period

[tex]T=2\pi \sqrt{l}{g}[/tex]

(This has the initial data for T and g)

What you want is

[tex]T'=2\pi \sqrt{l}{g'}[/tex]

and so

[tex]\frac{T'}{T}= \sqrt{\frac{g}{g'}}[/tex]
 
Last edited:
physixguru said:
Welcome to PF>

New time period is 1.324 seconds


Since it loses 0.102 second in 1 second
Time lost in 24 hrs will be = 0.102*60*60*24 = 8812.8 seconds
Whilst we appreciated the help physixguru, how does posting answers help the OP to understand the concept? Would it not be better to guide the student rather than just providing answers? Furthermore, your answers are incorrect.

jdeakons
I agree with your answer for the first question. As for the second question, how much longer is the period of the pendulum when g=9.797 m/s/s rather than the original value? Therefore, in the time taken for the first pendulum to measure 24 hours, how much time will have passed according to the second?
 
Last edited:
Hootenanny said:
Whilst we appreciated the help physixguru, how does posting answers help the OP to understand the concept? Would it not be better to guide the student rather than just providing answers? Furthermore, your answers are incorrect.

jdeakons
I agree with your answer for the first question. As for the second question, how much longer is the period of the pendulum when g=9.797 m/s/s rather than the original value? Therefore, in the time taken for the first pendulum to measure 24 hours, how much time will have passed according to the second?

I duly apologize, but for the clarification it was a typing error. i had copied the wrong data from the question.i respect the rules of the forum and promise to abide by it.This has happened with me the first time .
 

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