Period of a simple pendulum with a magnet under it

AI Thread Summary
The discussion revolves around determining the correct value of F/mg for a simple pendulum with a magnet underneath, with initial claims of 3 and 4 being debated. Participants emphasize that gravity still acts on the pendulum despite the presence of the magnet, which is crucial for accurate calculations. There is mention of additional forces, such as eddy currents, that could dampen the motion of the pendulum, complicating the analysis. The conversation also touches on the implications of superconductivity in relation to the pendulum's behavior. Ultimately, consensus leans towards agreeing with the value of F/mg being 3 when ignoring eddy currents.
MatinSAR
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Homework Statement
The period of a simple pendulum with an iron ball is T. If we put a magnet under it, its period becomes T/2. What is F/mg equal to?(F is the force that is exerted by the magnet.)
Relevant Equations
T = 2π Square root of√L/g
Hi ...
I have answered this question and I think that F/mg equals 3.
But I've asked it from someone and he told me that F/mg is 4.
Can someone help me find out which one is correct ???

My answer :
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I'm with you.
My guess is the other solver forgot gravity still acts when the magnet is present.
 
haruspex said:
My guess is the other solver forgot gravity still acts when the magnet is present.
Yes he said he ignored gravity.
Thank you for your time.
 
Just to be nit picking, there would be an additional force due to eddy currents induced in the iron ball as it swings past the magnet that will damp the motion.
 
kuruman said:
Just to be nit picking, there would be an additional force due to eddy currents induced in the iron ball as it swings past the magnet that will damp the motion.
Owing to a breakthrough in metallurgy, it is superconducting.
 
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kuruman said:
Just to be nit picking, there would be an additional force due to eddy currents induced in the iron ball as it swings past the magnet that will damp the motion.
What if we ignore eddy currents ? Because if it is not omitted, the periodicity is not defined for movement.
Do you agree with F/mg=3 in this case ?

haruspex said:
Owing to a breakthrough in metallurgy, it is superconducting.
I didn't understand ...
Can you please tell me if you disagree with my answer ...
 
MatinSAR said:
I didn't understand ...
Can you please tell me if you disagree with my answer ...
It was just an attempt at a humorous response to @kuruman's nitpick.
I agree with your answer.
 
haruspex said:
It was just an attempt at a humorous response to @kuruman's nitpick.
I agree with your answer.
I understand ...
Thanks again ...
 
I too agree with your answer. I am sorry that my attempt at levity confused you.
 
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kuruman said:
I too agree with your answer. I am sorry that my attempt at levity confused you.
I'm sorry I'm not a native speaker of English and this is why I didn't understand.
Thank you ...
 
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