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Period of Oscillation of a Meter Stick

  1. Oct 30, 2009 #1
    1. The problem statement, all variables and given/known data

    Measure the period of oscillation of a meter stick suspended at one end for small amplitudes.
    Does T = 2*sqrt(2I/mgL) when I is the rotational inertia about one end? Derive this relation.


    2. Relevant equations

    I = rotational inertia
    m = mass
    g = gravitational acceleration
    T = period of oscillation

    I=mr^2

    T=2*pi*sqrt(L/g)

    3. The attempt at a solution

    I'm not going to lie, I have no idea where to start. Previous period of oscillation problems with a simple pendulum or a spring/glider system were based off of the formula for period that included 2pi divided by the angular frequency. I don't know where the pi went or what to do with the r value if I was to substitute it in. HELP!
     
  2. jcsd
  3. Oct 31, 2009 #2

    rock.freak667

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    Homework Helper

    I think your equation is missing a π in it.


    Anyhow, try considering that at a small angle, what the height is (above the lowest point).

    For θ being small, what is cosθ and sinθ equal to?

    Now try conserving some energy.
     
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