Period of revolution of two double stars

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Homework Help Overview

The problem involves two double stars of equal mass rotating about their common center of mass, with a specified separation of 4 light years. The objective is to determine their period of revolution.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss using orbital equations and gravitational force relationships to find the period. There are attempts to clarify the use of reduced mass and the implications of the term "double stars." Questions arise regarding the dimensional correctness of the equations used and the interpretation of variables.

Discussion Status

The discussion is ongoing, with participants exploring different approaches and questioning assumptions. Some have provided corrections to earlier statements, while others are clarifying the setup of the problem, particularly regarding the forces acting on the stars and the definition of the radius in the context of their orbits.

Contextual Notes

Participants are working under the assumption of circular orbits and are considering the implications of the separation distance on the forces experienced by the stars. There is a noted confusion about the correct interpretation of the term "double stars" and how it relates to the number of stars involved in the problem.

leftnes
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Homework Statement


Two double stars of the same mass as the sun rotate about their common center of mass. Their separation is 4 light years. What is their period of revolution?


Homework Equations


Lagranian = T - U = \mu\dot{r}^{2}/2 + \vec{L}^{2}/2\mu r^{2} - Gm_{1}m_{2}/r
F = ma = m\omega^{2}r = Gm_{1}m_{2}/r


The Attempt at a Solution


Tried to solve this using the orbital equation , but I'm off by a power of 10. I've also tried using F = m\omega^{2}r = Gm_{1}m_{2}/r and solving for the period using \omega = 2\pi r/T but I'm not sure where I'm going wrong. Since the question asks for the period of two double stars, does this mean that the reduced mass is \mu = (2m_{1})(2m_{2})/(2m_{1} + 2m_{2}) = 4m^{2}/4m = m since all the masses are the same? I'm assuming that two double stars means 4 separate stars acting in pairs. I'm not really sure where to go with this problem.
 
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leftnes said:
F = m\omega^{2}r = Gm_{1}m_{2}/r
Aren't there a couple of things wrong with the RHS? It's dimensionally wrong for a force, no? And is r standing for the same distance each side?
 
Oops, yeah.

F = m\omega^{2}r = Gm_{1}m_{2}/r^{2}

I believe? Since \omega^{2} = a/r, I substituted for acceleration and set the only acting force on the stars as their gravitational attraction towards each other. Am I missing something else?
 
And assuming a circular orbit, r = .5d, where d is the separation between the stars.
 
leftnes said:
And assuming a circular orbit, r = .5d, where d is the separation between the stars.

If the separation is d, what force does each experience?
 

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