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greener1993

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The perpendicular bisector of a straight line joining the points (3,2) and (5,6) meets the x-axis at A and the y at B. Prove that the distance AB is equal to 6root5.

I just need to have theses checked to make sure there right, would love if you could just skim it and check :D

1)What is the gradient of the line perpendicular to y=3x-5. hence find the equation of the line which goes through (3,1) and is perpendicular to y=3x-5

a) to find the gradient I did, m2=-1/m1. m1=3 so it was -1/3 = -1/3

b) We know the coordinates (3,1) which is the y and X, so 1=(-1/3*3)+c

1=-1+c, so

2=C all together the answer is y=-1/3x+2

2)Find the equation of line B which is perpendicular to line A and goes though the mid-point.

I am given the coordinates for line A, (2,6) and (4,8). Using that i can find both the midpoint and the gradient of line A = midpoint = (3,7) Gradient = 1

So M2=1/M1 so -1/1=-1

we know from midpoint, y=7 and x=3 so

7=(-1*3)+c

7+3=c

10=c so the equation is Y=-x+10