- #1
Jameson
Gold Member
MHB
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Brie writes:
Hi everyone! I need a little help with finding a perpendicular line using an ordered pair and the equation to the previous line.
The equation is y= 3x+3 and the ordered pair is (1,1).
So far, I've used the slope-point equation to come up with such:
y-y1=m(x-x1)
y-1= -1/3(x-1)
y=(-1/3)(x)-(-1/3)(1)+1
At the end I ended up getting:
y=(-1/3)x+(1/3)+1
y=(-1/3)x+(4/3)
When I graph it, it's not going through the point (1,1) which it should. What am I doing wrong?
Thank you!
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