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I'm having some issues about the Newtons third law.
The image should represent a person in a bus with and the forces acting on them.
The bus and the person are observed from outside the bus. The bus starts accelerating because of the force [itex]F_{BUS MOVING}[/itex]. This force represent the resultant force of the friction between the bus and the ground, and the buses starting force.
As a result, friction force [itex]F_{PBUS}[/itex] occurs and it acts on the bus because of the mass of the person.
As a reaction, a force of the same size but opposite direction acts on the person [itex]F_{BUSP}[/itex]
What is the sum of the forces on the bus?
[itex]F_{BUS MOVING}F_{PBUS}[/itex] ?
How would one calculate [itex]F_{PBUS}[/itex] by knowing the mass of the person and [itex]\mu[/itex]?
Is this the solution?
[itex]F_{BUS MOVING}F_{PBUS}=F_{BUSP}[/itex]
Since in this case, the bus and the person have the same value and orientation. That is what a observer from the street would see, right?
I'm having some issues about the Newtons third law.
The image should represent a person in a bus with and the forces acting on them.
The bus and the person are observed from outside the bus. The bus starts accelerating because of the force [itex]F_{BUS MOVING}[/itex]. This force represent the resultant force of the friction between the bus and the ground, and the buses starting force.
As a result, friction force [itex]F_{PBUS}[/itex] occurs and it acts on the bus because of the mass of the person.
As a reaction, a force of the same size but opposite direction acts on the person [itex]F_{BUSP}[/itex]
What is the sum of the forces on the bus?
[itex]F_{BUS MOVING}F_{PBUS}[/itex] ?
How would one calculate [itex]F_{PBUS}[/itex] by knowing the mass of the person and [itex]\mu[/itex]?
Is this the solution?
[itex]F_{BUS MOVING}F_{PBUS}=F_{BUSP}[/itex]
Since in this case, the bus and the person have the same value and orientation. That is what a observer from the street would see, right?
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