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I'm having some issues about the Newtons third law.

The image should represent a person in a bus with and the forces acting on them.

The bus and the person are observed from outside the bus. The bus starts accelerating because of the force [itex]F_{BUS MOVING}[/itex]. This force represent the resultant force of the friction between the bus and the ground, and the buses starting force.

As a result, friction force [itex]F_{P-BUS}[/itex] occurs and it acts on the bus because of the mass of the person.

As a reaction, a force of the same size but opposite direction acts on the person [itex]F_{BUS-P}[/itex]

What is the sum of the forces on the bus?

[itex]F_{BUS MOVING}-F_{P-BUS}[/itex] ?

How would one calculate [itex]F_{P-BUS}[/itex] by knowing the mass of the person and [itex]\mu[/itex]?

Is this the solution?

[itex]F_{BUS MOVING}-F_{P-BUS}=F_{BUS-P}[/itex]

Since in this case, the bus and the person have the same value and orientation. That is what a observer from the street would see, right?

I'm having some issues about the Newtons third law.

The image should represent a person in a bus with and the forces acting on them.

The bus and the person are observed from outside the bus. The bus starts accelerating because of the force [itex]F_{BUS MOVING}[/itex]. This force represent the resultant force of the friction between the bus and the ground, and the buses starting force.

As a result, friction force [itex]F_{P-BUS}[/itex] occurs and it acts on the bus because of the mass of the person.

As a reaction, a force of the same size but opposite direction acts on the person [itex]F_{BUS-P}[/itex]

What is the sum of the forces on the bus?

[itex]F_{BUS MOVING}-F_{P-BUS}[/itex] ?

How would one calculate [itex]F_{P-BUS}[/itex] by knowing the mass of the person and [itex]\mu[/itex]?

Is this the solution?

[itex]F_{BUS MOVING}-F_{P-BUS}=F_{BUS-P}[/itex]

Since in this case, the bus and the person have the same value and orientation. That is what a observer from the street would see, right?

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