Pf = Pi * (Vi/Vf)^5/3 (since gamma = 5/3 for a monatomic gas)

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Discussion Overview

The discussion revolves around the application of the adiabatic process equations for an ideal monatomic gas. Participants are attempting to calculate the final pressure and temperature after compressing the gas in a specified volume, while clarifying the derivation of the relevant equations.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Homework-related

Main Points Raised

  • One participant presents a problem involving the compression of an ideal monatomic gas and expresses confusion about the derivation of the equation pf = pi*(Vi/Vf)^5/3.
  • Another participant explains that for adiabatic processes, the relationship P*V^gamma = constant applies, where gamma is the ratio of heat capacities, specifically 5/3 for a monatomic gas.
  • A later reply clarifies that pf = Pi*(Vi/Vf)^gamma follows from the constant relationship of the adiabatic process, reiterating the derivation of the equation.

Areas of Agreement / Disagreement

Participants express confusion about the derivation of specific equations related to adiabatic processes, indicating that there is no consensus on the understanding of these relationships.

Contextual Notes

Participants reference the ideal gas law and the concept of adiabatic processes but do not resolve the underlying assumptions or steps in the derivation of the equations discussed.

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One mole of an ideal monatomic gas, initially at 1 atm pressure, is surrounded by adiabatic walls in a container of volume 0.01 m3 . The gas is compressed until the volume is 1/8 of the original volume. Calculate the final pressure and temperature.

^^ I'm having problems following this question. Its only a short answer, but I'm confused none the less!

A: pV^5/3 = constant.
pf = pi(Vi/Vf )^5/3 = 1(8)^5/3 = 25 = 32 atm.
Tf = pfVf /nR = 32 × (0.01/8)101325/8.314 = 487.5 K

I understand the last line in normal ideal gas equation, but the first two lines, which reference the equation: pV^5/3 = constant has thrown me, i don't know how the second line follows (where does pf=pi*(vi/vf)^5/3 come from? i see its similar to the constant equation
 
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125.6 said:
One mole of an ideal monatomic gas, initially at 1 atm pressure, is surrounded by adiabatic walls in a container of volume 0.01 m3 . The gas is compressed until the volume is 1/8 of the original volume. Calculate the final pressure and temperature.

^^ I'm having problems following this question. Its only a short answer, but I'm confused none the less!

A: pV^5/3 = constant.
pf = pi(Vi/Vf )^5/3 = 1(8)^5/3 = 25 = 32 atm.
Tf = pfVf /nR = 32 × (0.01/8)101325/8.314 = 487.5 K

I understand the last line in normal ideal gas equation, but the first two lines, which reference the equation: pV^5/3 = constant has thrown me, i don't know how the second line follows (where does pf=pi*(vi/vf)^5/3 come from? i see its similar to the constant equation

For adiabatic processes (no heat exchanged withthe surroundings) in ideal gases, P*V^gamma = constant. Gamma is the ratio of the heat capacities at constant pressure and constant volume. For an ideal monatomic gas, C_v = 3/2 * R, and C_p = 5/2* R, so gamma = (5/2 * R) / (3/2 * R) = 5/3.

http://en.wikipedia.org/wiki/Adiabatic_process
 
Quantum Defect said:
For adiabatic processes (no heat exchanged withthe surroundings) in ideal gases, P*V^gamma = constant. Gamma is the ratio of the heat capacities at constant pressure and constant volume. For an ideal monatomic gas, C_v = 3/2 * R, and C_p = 5/2* R, so gamma = (5/2 * R) / (3/2 * R) = 5/3.

http://en.wikipedia.org/wiki/Adiabatic_process

Yeah, thanks

The part i still don't understand is how the equation pf = pi*(vi/vf)^5/3 follow?
 
125.6 said:
Yeah, thanks

The part i still don't understand is how the equation pf = pi*(vi/vf)^5/3 follow?
Pf * Vf^gamma = constant = Pi * Vi^gamma
Pf = Pi * (Vi/Vf)^gamma
 

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