Phase Diagram Composition Determination

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SUMMARY

The discussion focuses on determining the composition of the Cu-Zr alloy at 300°C using the lever rule. The calculations reveal that the alloy consists of 64.7% Cu10Zr7 and 35.3% CuZr2. The atomic percentages used in the calculations are C0=0.5, Cα=0.41, and Cβ=0.665. The methodology applied is consistent with standard practices in phase diagram analysis.

PREREQUISITES
  • Understanding of phase diagrams, specifically the Cu-Zr phase diagram.
  • Knowledge of the lever rule for phase composition calculations.
  • Familiarity with atomic percent calculations in alloy systems.
  • Basic principles of thermodynamics as they apply to phase transitions.
NEXT STEPS
  • Study the Cu-Zr phase diagram in detail to understand its features and implications.
  • Learn more about the lever rule and its applications in different alloy systems.
  • Explore atomic percent calculations and their significance in materials science.
  • Investigate the thermodynamic principles governing phase transitions in alloys.
USEFUL FOR

Materials scientists, metallurgists, and students studying phase diagrams and alloy compositions will benefit from this discussion.

sara06
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Homework Statement



Reference the Cu-Zr phase diagram. If you make the alloy CuZr and heat it to 300°C, what percentage of the material will be Cu10Zr7 and what percentage of the material will be CuZr2?

Homework Equations



Phase diagram attached.

The Attempt at a Solution



I used the lever rule. I called the alpha phase Cu10Zr7 and the beta phase CuZr2. In terms of atomic percent Zr, I have C0=0.5, Cα=0.41, and Cβ=0.665. Then the atomic percent alpha phase is (Cβ-C0)/(Cβ-Cα) which is 64.7 percent. The atomic percent beta is (C0-Cα)/(Cβ-Cα) which is 35.3 percent. So I have 64.7% Cu10Zr7 and 35.3% CuZr2.
 

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    Cu-Zr.jpg
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sasa06, Welcome To Physics Forums.

Your calculation looks correct.
 
thanks!
 

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