Phase Difference of Wave and Reflected Wave

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SUMMARY

The discussion centers on calculating the phase difference between a direct sound wave and its reflected counterpart, originating from a source transmitting at a frequency of 115 Hz with a sound speed of 345 m/s. The total distance for the reflected wave is 26 meters, while the direct wave travels 24 meters. The calculated phase difference is 4.189 radians (240 degrees), but the correct answer, considering the phase change upon reflection from a fixed end, is 1.047 radians (60 degrees) after accounting for the additional π phase shift.

PREREQUISITES
  • Understanding of wave properties, specifically sound waves.
  • Knowledge of wave frequency and speed calculations.
  • Familiarity with phase difference equations, particularly Δφ = 2π(d/λ).
  • Concept of phase shifts due to reflection from fixed boundaries.
NEXT STEPS
  • Study the derivation of wave speed and wavelength using the formula λ = v/f.
  • Explore the concept of phase shifts in wave mechanics, especially for fixed and free boundaries.
  • Investigate the implications of phase differences in sound wave interference patterns.
  • Learn about practical applications of phase difference calculations in acoustics and engineering.
USEFUL FOR

Students studying wave mechanics, acoustics enthusiasts, and anyone involved in sound engineering or physics education will benefit from this discussion.

lordy2010
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Homework Statement


A source is transmitting a sound wave of frequency 115 Hz. A receiver detects the direct sound wave and the sound reflected from a small section of wall. Speed of sound is 345 m/s.

It also gives a diagram of sound waves leaving a source, one hitting the wall, reflecting, and traveling a total of 26 metres to reach the receiver and the other going 24 metres directly to the receiver.

What is the phase difference between the direct and reflected wave?

Homework Equations



\lambda = \frac{v}{f}

\Delta\phi = 2\pi\frac{d}{\lambda}

The Attempt at a Solution



I thought the phase difference was just kd, where k = 2pi / wavelength. So I went and figured out d which is 26 - 24 = 2, and wavelength, which turned out to be 3 m.
I got as my answer 4.189 radians (240 degrees).
Then, when I looked at the solution for the problem, they had done the same thing as me, but they put +- pi at the end... So they got 4.189 +- pi = 1.047 radians (60 degrees).
But even after looking at the soluton, I have no idea why they put the +- pi at the end...
 
Physics news on Phys.org
There is pi phase change when the wave reflects from the wall. The wall is a "fixed end".

ehild
 
Thanks a lot! I completely forgot about that :-P
 

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