Phase Transitions Exist Only In the Thermodynamic Limit Or

In summary, the existence of phase transitions in a system is often only observed in the thermodynamic limit, where the free energy per site may have a discontinuity at H=0. However, in a finite system with N spins, the free energy is not directly proportional to N, making it difficult to establish a phase transition without taking the thermodynamic limit. This is supported by the proof that the total free energy F(H) is only proportional to N in the thermodynamic limit, and not in a finite system.
  • #1
maverick_starstrider
1,119
6
It is often said that phase transitions only exist in the thermodynamic limit based on some proof like:

-A system has time-reversal symmetry thus its TOTAL free energy F(H)=F(-H) (H is the field) therefore the magnetization is

[tex]M(H)=\frac{\partial F(H)}{\partial H}=\frac{\partial F(-H)}{\partial(- H)}=-\frac{\partial F(-H)}{\partial H}=-M(H) [/tex]

Thefore, [tex]M(H)=-M(H)[/tex] therefore at [tex]M=0[/tex] we have

[tex]M(0)=-M(0)[/tex] therefore M(0)=0, thus no spontaneous magnetization. However, in the thermodynamic limit [tex]f(H)[/tex] (the free energy per site) may have a discontinuity at H=0 and therefore the above is not necessarily true, and so on thus true phase transitions only exist in the thermodynamics limit.

Here's where I get confused. Can we not just say that the total free energy F(H) for a finite system of N spins is really [tex]F(H)=N f(H)[/tex] and the same argument applies. Therefore, isn't it really just the case the the thermodynamic limit EXIST and not necessarily that the system be at it?
 
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  • #2
Let [itex]f_N(H) = F(H)/N[/itex]. Let

[tex]f_\infty(H) = \lim_{N\rightarrow \infty} f_N(H)[/tex].

[itex]f_\infty(H)[/itex] and [itex]f_N(H)[/itex] are not the same function. The free energy F(H) is only proportional to N in the thermodynamic limit. For example, the free energy of a 1d Ising ring is [itex]F(H) = -kT\log(\lambda_1(H,T)^N+\lambda_2(H,T)^N)[/itex], where the lamba's are eigenvalues of a certain matrix, and [itex]\lambda_1 > \lambda_2[/itex] (except when T = 0). You can check that under these conditions it is only when [itex]N \rightarrow \infty[/itex] that F(H) is asymptotically proportional to N. Hence, in general, [itex]f_\infty(H)[/itex] has a discontinuity at H = 0, as you have said, but [itex]f_N(H)[/itex] does not.

The operations of taking [itex]N \rightarrow \infty[/itex] and the derivation of the free energy do not commute, so you cannot establish the phase transition without the thermodynamic limit.
 
  • #3

1. What is the thermodynamic limit and why is it important in phase transitions?

The thermodynamic limit refers to the theoretical concept of taking a system to an infinitely large size. In phase transitions, this limit is important because it allows us to study the behavior of the system at the critical point, where small changes in temperature or pressure can cause significant changes in the system's properties.

2. Can phase transitions occur in systems that are not in the thermodynamic limit?

No, phase transitions are only observed in systems that are in the thermodynamic limit. This is because phase transitions are a collective phenomenon that involves the behavior of a large number of particles, and the thermodynamic limit allows us to accurately describe this behavior.

3. How does the thermodynamic limit affect the properties of a system near a phase transition?

In the thermodynamic limit, the properties of a system near a phase transition become highly sensitive to small changes in temperature or pressure. This is due to the fact that the system is at the critical point, where small changes can cause large fluctuations and changes in the system's properties.

4. Are there any exceptions to the rule that phase transitions only occur in the thermodynamic limit?

There are some rare cases where phase transitions can occur in systems that are not in the thermodynamic limit. These are known as non-equilibrium phase transitions and are typically observed in systems that are driven out of equilibrium by an external force or perturbation.

5. How does the thermodynamic limit affect the study and understanding of phase transitions?

The thermodynamic limit is crucial in the study and understanding of phase transitions as it allows us to make accurate predictions and calculations about the behavior of the system at the critical point. Without the thermodynamic limit, our understanding of phase transitions would be limited and incomplete.

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