Phasors and steady-state solutions

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SUMMARY

The discussion focuses on using phasors to evaluate the steady-state solution for the differential equation f'' + 1.5f' + f = Ce^2tj. The user attempts to find a trial solution by substituting f = Ce^2tj and calculating its derivatives, leading to incorrect conclusions. The correct approach involves substituting f = Ae^2tj and simplifying the equation, ultimately leading to A = C/(4t^2 + 3t + 1). This method highlights the importance of correctly applying phasor techniques in solving differential equations.

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  • Understanding of phasors in electrical engineering
  • Familiarity with differential equations
  • Knowledge of trial solutions in solving ODEs
  • Basic calculus for differentiation
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  • Study the application of phasors in solving linear differential equations
  • Learn about the method of undetermined coefficients for trial solutions
  • Explore the concept of steady-state solutions in dynamic systems
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Students and professionals in engineering, particularly those studying electrical engineering and control systems, as well as anyone interested in solving differential equations using phasor methods.

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Homework Statement


use phasors to evaluate the steady-state solution to the equation f'' + 1.5f' + f = Ce^2tj


Homework Equations





The Attempt at a Solution


let f = Ce^2tj (this is a 'trial solution', i think)

f' = 2tCe^2tj
f'' = 4(t^2)Ce^2tj

therefore 4(t^2)Ce^2tj + 3tCe^2jt + Ce^2tj = Ce^2tj
4t^2 + 3t = 0

therefore t = 0 and t = -3/4
therefore f = C and f = Ce^-1.5tj.

^ the above is NOTHING like the answer. what am i doing wrong?
 
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attempt #2:

f = Ae^2tj
f' = 2tAe^2tj
f'' = 4(t^2)Ae^2tj

so...

4(t^2)Ae^2tj + 3Ate^2tf + Ae^2tj = Ce^2tj

dividing through by e^2tj gives

A(4t^2 + 3t + 1) = C

so A = C/(4t^2 + 3t + 1)? that's still not the answer
 

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