Calculating the arc length in r^3

Click For Summary

Homework Help Overview

The discussion revolves around calculating the arc length of a vector function defined in three-dimensional space, specifically r(t) = (t, 2t, t^2 - 3) for the interval 0 ≤ t ≤ 2. Participants are exploring the application of the arc length formula and its implications in this context.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to understand how to apply the arc length formula, questioning the necessity of using a specific provided formula versus a more straightforward differentiation approach. There is also inquiry into the calculation of |dr/dt| and its relevance to the problem.

Discussion Status

The discussion is ongoing, with some participants expressing confusion about the requirements of the problem and the formula to be used. Guidance has been offered regarding the differentiation of the vector function and the integration process, but there is no explicit consensus on the best approach yet.

Contextual Notes

Participants note that the problem comes with specific instructions from a textbook, which may be influencing their approach and understanding of the arc length calculation. There is mention of a visual aid that may provide additional context, but its details are not fully explored in the discussion.

makman09
Messages
3
Reaction score
0

Homework Statement



r(t)=ti+2tj+(t^2-3)k or r(t)=(t, 2t, t^2-3)

0≤t≤2

Homework Equations



arc length formula ∫[the scalar of dr/dt]
I know I can calculate the arc length through the equation above, but the questions asks for
me to utilize this formula.

∫√(t^2+a^2) dt = .5t√(t^2+a^2) + .5a^2 times ln(t+√(t^2+a^2))

The Attempt at a Solution


I couldn't get far on this, but i think it has to do something with another alternative to get the arc length.

If it is difficult reading the problem, i also have a picture of it.
 
Physics news on Phys.org
Here is the picture of the image
It's #6
 

Attachments

  • photo.jpg
    photo.jpg
    32.1 KB · Views: 520
What is the |dr/dt| in this case?
 
makman09 said:

Homework Statement



r(t)=ti+2tj+(t^2-3)k or r(t)=(t, 2t, t^2-3)

0≤t≤2

Homework Equations



arc length formula ∫[the scalar of dr/dt]
I know I can calculate the arc length through the equation above, but the questions asks for
me to utilize this formula.

∫√(t^2+a^2) dt = .5t√(t^2+a^2) + .5a^2 times ln(t+√(t^2+a^2))

The Attempt at a Solution


I couldn't get far on this, but i think it has to do something with another alternative to get the arc length.

If it is difficult reading the problem, i also have a picture of it.
What, exactly, is your problem? It should be very easy to differentiate that. Have you done that yet? There is no "alternative" needed. Just take the derivative of the vector function, find its length and integrate that.
 
i know right? but the book keeps telling me to use the formula to find the arc length provided with problem number 6.
 
makman09 said:
i know right? but the book keeps telling me to use the formula to find the arc length provided with problem number 6.

So show us what you get for the integral using the "usual way" and explain why you can't use the given formula. Then we can see what the issue really is for you.
 

Similar threads

Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 10 ·
Replies
10
Views
1K
Replies
3
Views
2K
Replies
5
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K