Phonon Dispersion Relation: Reflection of Photons Explained

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in the dispersion relation curve for phonon, optical branch is not zero at k = 0. Thus generally speaking solid might be transparent for all photon wavelengths except the wavelength which corresponds to the energy of an optical phonon at k = 0. Thus photons can be absorbed or reflected. It says that about 90 percents of photons are reflected. Why?

Also, It is not clear for me how photon can be reflected? It requires to change the direction of the k vector, to opposite direction. Or is it that incident photon converts to optical phonon, which then converts to optical photon in opposite direction statistically?

I am on a master level.
Thank you.
 
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The momentum of infrared photons is negligible. The optical phonons near the center of the Brillouin zone are like large electrical dipole oscillators, which gives a very strong interaction with the electromagnetic waves.
 
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Hi. I have got question as in title. How can idea of instantaneous dipole moment for atoms like, for example hydrogen be consistent with idea of orbitals? At my level of knowledge London dispersion forces are derived taking into account Bohr model of atom. But we know today that this model is not correct. If it would be correct I understand that at each time electron is at some point at radius at some angle and there is dipole moment at this time from nucleus to electron at orbit. But how...
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