Photoelectric effect and cutoff frequency

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Homework Help Overview

The discussion revolves around the photoelectric effect, specifically focusing on how to determine the cutoff frequency from a graph of Stopping Potential versus Frequency of light. Participants are examining the relationship between stopping potential and frequency, using provided data points.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the theoretical and actual values of the slope of the graph and how these relate to the cutoff frequency. There are inquiries about the significance of the y-intercept and its relation to the work function.

Discussion Status

Some participants have offered guidance on rearranging equations and comparing them to the equation of a straight line to identify key graph features. Multiple interpretations of the graph's intercepts are being explored, particularly regarding their physical significance.

Contextual Notes

There is a mention of theoretical versus actual values for the slope, which may indicate discrepancies in measurements or calculations. Participants are also questioning the implications of the graph's intercepts without reaching a consensus.

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Homework Statement


I was just wondering that when I have a graph of the Stopping Potential versus Frequency of the light. How can I find the value for the cutoff frequency?
Wavelength Vo
160 nm 2.99 V
53 nm 19.18 V
80 nm 11.00 V
160 nm 2.93 V
187 nm 1.92 V

Homework Equations


The Attempt at a Solution

 
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What attempt have you made?
 
Write down the equation for the photoelectric effect and then use the fact that the stopping potential is the work done in stopping the electrons from having any kinetic energy.
 
Dadface said:
What attempt have you made?

well i found the theoretical value of the slope: 4.14125 X 10^-15 Js/C and the actual value of the slope: 3.9512 X 10^15 J s/C but don't know how to use them to find the answer
 
As rockfreak advised write down the equation.Next rearrange it to make V the subject of the equation and then compare what you have to the equation of a straight line.By comparison you should be able to identify what the gradient of the graph represent and what the intercepts on the y and the x-axis represent.
 
Last edited:
Dadface said:
As rockfreak advised write down the equation.Next rearrange it to make V the subject of the equation and then compare what you have to the equation of a straight line.By comparison you should be able to identify what the gradient of the graph represent and what the intercepts on the y and the x-axis represent.

does the y intercept of the graph represent the work function?
 
Did you plot V on the y axis?If so the intercept has the units of volts ie joules per coulomb.The work function has the units of Joules so what could the intercept represent?Also, look at the intercept on the x axis.
 

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